Let us suppose that there is a command such as:

# uname -a
Linux (none) 2.6.24 #155 PREEMPT Thu Nov 16 09:41:07 IST 2017 ppc GNU/Linux

Now, my question is: Are there any commands which will only print:

Nov 16 09:41:07 IST 2017

And could you please explain the command a little? Thank you! in advance.

  • 3
    Not sure what your application is. Are you looking for a command to extract 7th to 11th fields (delineated by blanks) of a line or are you asking to search a line to find a date, or are you asking to get the date of the kernel, or is this a homework assignment and your instructor lacks imagination and clear instructions? – WinEunuuchs2Unix Jan 16 '18 at 4:48
  • Has any of the answers helped you? Please accept it or clarify your needs using editing or comments. – Melebius Jan 24 '18 at 7:35

This awk will do that using this variable:

uname -a | awk '{ print $7,$8,$9,$10,$11 }'


Nov 16 09:41:07 IST 2017
  • awk: start awk program
  • '{ print $7,$8,$9 }': print the 7th, 8th and 9th fields with , spaces between these values.
  • uname -a |: pipe the result of uname -a to the awk command for processing
  • This does not work in my case where the field count differs. uname -a gives Linux MiM-testsrv-ubuntu 4.4.0-72-lowlatency #93-Ubuntu SMP PREEMPT Fri Mar 31 15:14:04 UTC 2017 i686 i686 i686 GNU/Linux, the result of your command: Fri Mar 31 15:14:04 UTC – Melebius Jan 16 '18 at 7:43
  • This is not a one-to-one support site but a public knowledge base, so we should post universally usable answers. If they have some caveats, we should warn about them. – Melebius Jan 16 '18 at 7:55
  • Melebius Now, why would you assume OP wants to use the command uname -v rather than uname -a perhaps you know the OP? I don't second guess OPs I do as requested and add any extra for the general public. – George Udosen Jan 16 '18 at 8:07
  • As WinEunuuchs2Unix correctly pointed out, the question is ambiguous. You chose one option from the possibilities mentioned by WinEunuuchs2Unix, I chose another. Hopefully, OP will come back and clarify their needs. In the meantime (which may also grow to infinity), we should clarify the assumptions valid for our solutions. – Melebius Jan 16 '18 at 9:21

The command uname -a prints all the information about your kernel while uname -v only prints kernel version which is the part ending with the date:

$ uname -v
#155 PREEMPT Thu Nov 16 09:41:07 IST 2017

You can use the tail -c command to print the end of the string with the specified length.

uname -v | tail -c25

This works well also in my case where the count of spaces differs.

$ uname -v
#93-Ubuntu SMP PREEMPT Fri Mar 31 15:14:04 UTC 2017
$ uname -v | tail -c25
Mar 31 15:14:04 UTC 2017
  • And what is the result of uname -a | tail -c25 as I see OP used uname -a and not uname -v. Please direct your questions to Op to clarify any ambiguities! – George Udosen Jan 16 '18 at 8:10
  • @GeorgeUdosen I had explained it in the beginning of my answer. I’ve just added a bit more information, please check it now. – Melebius Jan 16 '18 at 9:06

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