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I am new to Linux but not Python. I am trying to migrate my Python skills to Linux. With Windows I can open an image file with the default viewer using.

import os
os.system(r"C:\gTemp\Capture.JPG")

Using a valid Linux path the same code returns 'Permission denied'

import os
os.system(/home/myname/Capture.JPG")

Why am I getting this error and how do I fix it? I am using 16.04 with Python 2.7

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  • Invalid path? 'C:' has no meaning in Linux. – user535733 Oct 18 '17 at 22:07
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    JPEG files aren't executable by themselves, and the system doesn't know what application you want to use to open therm: perhaps you should be using something like system("xdg-open /home/myname/Capture.JPG") - or (probably better) use subprocess.call as described here: How to open a file with the standard application? – steeldriver Oct 18 '17 at 22:51
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os.system() executes the command that is passed to it. An image is not a command. Windows may execute an app to open the image, but that is Windows specific. The subprocess.call is your best bet as mentioned by steeldriver.

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