13

I have a file with all the tests name:

$ cat all_tests.txt
test1
test2
test3
test4
test5
test6

And another file containing the test names and the associated result:

$ cat completed_tests.txt
test1 Passed
test3 Failed
test5 Passed
test6 Passed

How to create a new file containing all the test names with the associated result without duplicates?

If I execute:

sort all_tests.txt completed_tests.txt

The output contains duplicates:

test1 
test1 Passed
test2
test3 
test3 Failed
test4
test5 
test5 Passed
test6 
test6 Passed

The desired output:

test1 Passed
test2
test3 Failed
test4
test5 Passed
test6 Passed
18

Seems like you can achieve this with join very easily if the files are both sorted.

$ join -a 1 all_test.txt completed_test.txt
test1 Passed
test2
test3 Failed
test4
test5 Passed
test6 Passed

-a 1 means print lines from file 1 that had nothing joined to them.

If your files are not already sorted, you can use this (thanks terdon!):

join -a 1  <(sort all_tests.txt) <(sort completed_tests.txt )
0
7

The right tool here is join as suggested by @Zanna, but here's an awk approach:

$ awk 'NR==FNR{a[$1]=$2; next}{print $1,a[$1]}' completed_tests.txt all_tests.txt 
test1 Passed
test2 
test3 Failed
test4 
test5 Passed
test6 Passed
2

Perl

Effectively, this is a port of terdon's answer:

$ perl -lane '$t+=1; $h{$F[0]}=$F[1] if $.==$t; print $F[0]," ",$h{$F[0]} if $t!=$.;$.=0 if eof' completed_tests.txt all_tests.txt          
test1 Passed
test2 
test3 Failed
test4 
test5 Passed
test6 Passed

This works by building hash of test-status pairs from completed_test.txt and then looking up lines in all_tests.txt in that hash. The $t variable of total lines processed from each file and $. that is reset upon reaching end of file, allow us to keep track of which file is currently read.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.