How to run a command separated in several variables in Bash?

Question

I would like to run a command made of several "pieces".

php="php"
options="-l"

for f in `git diff-index --cached --name-only HEAD | grep -e '\(php\|phtml\)$'`; do
   if [ -f $f ]; then
       # Here I want to run my command defined
       # in $php and $options and put the result in
       # $php_lint var
       # like this command would do:
       # php_lint=$(php -l $f)
       # but with something like that:
       # php_lint=eval $php $options $f
   fi
done

How can I do this?

Update:

After struggle on a particular point, I asked this question :

• https://stackoverflow.com/questions/43760897/bash-error-command-not-found-running-a-command-stored-in-var/

Please have a look, it could also help you.

Answer 1

Put the options in an array, and expand it as "${options[@]}"

Ex.

$ cmd=ls
$ options=(-a -l -d)
$ f="foo"

then

$ result=$("$cmd" "${options[@]}" "$f")

giving

$ echo "$result"
drwxrwxr-x 2 user user 4096 Apr 20 08:07 foo