sed the string and hold the value in new variable

Question

I have this String cap/media/101/101.mp4 and I need to cut the 101 in another Variable.

I am trying to do it with sed but it's not giving me the output I need.

echo cap/media/101/101.mp4 | sed -e 's/d/\(.*\)/\1/'

can someone please give an idea about it?

Answer 1

Assuming consistent fields, a simple awk command can do the trick:

echo cap/media/101/101.mp4 | awk -F"/" '{print $3}'

Output:

101

Answer 2

Assuming you want the characters between media/ and the next / (based on what you said in the comments) you could cut that part with

sed -r 's|.*media/([^/]+).*|\1|'

Explanation

• -r use ERE (so we don't have to escape () or + to use them as metacharacters
• s|old|new| replace old with new (using an alternative delimiter to avoid having to escape / in the string)
• ([^/]+) save some characters that are not /
• \1 the saved pattern (the rest is discarded)

Answer 3

(Late to the party :)). So many ways to skin this cat...Here are a few:

Here, i am getting the digits surrounded by /:

With cut:

cut -d/ -f3 

With grep:

grep -Po '/\K\d+(?=/)'

With perl:

perl -F/ -lane 'print $F[2]'

With python:

python3 -c 'import sys; i=sys.stdin.read().split("/"); print(i[2])'

Another sed:

sed -E 's#.*/([0-9]+)/.*#\1#' 

Another awk (though the already provided awk answer getting the / delimited 3rd field should be the way to go):

awk '{i=gensub(".*/([0-9]+)/.*", "\\1", "g"); print i}'

With go:

package main

import (
    "fmt"
    "strings"
)

func main() {
    str := "cap/media/101/101.mp4"
    fmt.Println(strings.Split(str, "/")[2])
}

Example:

% cut -d/ -f3 <<<'cap/media/101/101.mp4'                                                          
101

% grep -Po '/\K\d+(?=/)' <<<'cap/media/101/101.mp4'
101

% perl -F/ -lane 'print $F[2]' <<<'cap/media/101/101.mp4'                                         
101

% python3 -c 'import sys; i=sys.stdin.read().split("/"); print(i[2])' <<<'cap/media/101/101.mp4'
101

% sed -E 's#.*/([0-9]+)/.*#\1#' <<<'cap/media/101/101.mp4'
101

% awk '{i=gensub(".*/([0-9]+)/.*", "\\1", "g"); print i}' <<<'cap/media/101/101.mp4'
101

## Go Playground: https://play.golang.org/p/kGdzyywEB2