I have a json file where I need to remove the last forward slashes only. See the example:


I just want the data to look like:


How can I do this with sed?

  • 1
    Backslash or a (forward) slash? – Melebius Feb 7 '17 at 10:07
  • 1
    How big is the file, and can double slash blindly be replaced by a single one? – Jacob Vlijm Feb 7 '17 at 11:52
  • 1
    Your output doesn't have the http:// from the input. – muru Feb 8 '17 at 4:44
  • 1
    Removing http:// should be easy, just another sed 's,http://,,g' – muru Feb 8 '17 at 5:30
  • 4
    If I may voice my opinion, @JafferWilson , consider starting to learn using Python or Perl and their respective json APIs (and maybe learn those in the process ). I understand it's fun and simple sometimes to use sed or other tools, but json APIs were created specifically for that purpose. Of course, structuring json data properly. Not trying to teach you what to do, but seriously - you can save yourself a lot of time if you start using proper tools for proper job. – Sergiy Kolodyazhnyy Feb 8 '17 at 5:32

I took the liberty to modify OP's input slightly, because as it stands , it's not properly structured json data (due to the {...} part) and implemented a small python script that works with multiple dictionaries, assuming that we're dealing with a dictionary per line. Additionally, as has been discussed in the comments to the question, OP also wanted to remove http:// part.

The script below implements everything discussed above.

#!/usr/bin/env python
import json,sys

with open(sys.argv[1]) as f: 
    for line in f:
        if data["url"][-1] == '/':
        if data["originalUrl"][-1] == '/':

Test run:

$ cat input.txt                                                                                 
{"url":"http://example.com/vary/file/","originalUrl":"http://example.com/vary/file/","applications":[{"somedata": "blah"}]}
{"url":"http://another-example.com/vary/file/","originalUrl":"http://example.com/vary/file/","applications":[{"somedata": "blah"}]}
$ ./remove_slash.py input.txt                                                                   
{"url": "example.com/vary/file", "applications": [{"somedata": "blah"}], "originalUrl": "example.com/vary/file"}
{"url": "another-example.com/vary/file", "applications": [{"somedata": "blah"}], "originalUrl": "example.com/vary/file"}
| improve this answer | |

If you insist on using sed, you could just match the /" combination, to remove the last / in every field, assuming it will not occur somewhere you want to keep it (which should be fairly reliable in this case)

$ sed 's|/"|"|g' file

I used | to delimit instead of / to save a backslash. You need g for multiple matches on the same line.

Here's a way to take out the http:// as well in the same call:

$ sed -r 's|"http://([^"]+)/"|"\1"|g' url

([^"]+) will match anything between "http:// and /" that isn't a ". We save this part with () and reference with \1.

| improve this answer | |

A late one:

a simple, purely text based python option:

#!/usr/bin/env python3
import sys

with open(sys.argv[1]) as data:
    for l in data:
        print(("").join(l.strip().replace("http://", "").rsplit("/", 1)))

Or, just for fun, another way of saying it:

#!/usr/bin/env python3
import sys

[print(("").join(l.strip().replace("http://", "").rsplit("/", 1))) for l in open(sys.argv[1])]

doing both the string replacement/removal (http://) and the slash removal in appr. 47 seconds on 14.000.000 million lines, on my ancient system.

To use:

python3 /path/to/script.py /path/to/inputfile > outputfile


As usual, python is quite readable, but in detail:

  • rsplit("/", 1) splits the line from the right (hence the r) by the delimiter / only once (hence the 1)
  • l.replace("http://", "") replaces http:// by an empty string
  • ("").join() joins the list, that was created by rsplit() again into a line
| improve this answer | |

Input JSON file (test.json):

  • Code to modify as per requirement and re-write to same file:

    import json
     with open("test.json") as fh:
        data = json.load(fh)
     for k,v in data.items():
        data[k] = v.replace("http://","").strip("/")
     with open("test.json","w") as fh:


{"url": "example.com/vary/file", "originalUrl": "example.com/vary/file"}

All operations at once, replaces http:// with "" and strips / at the end of the string.

| improve this answer | |

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