0

I have a SIP account with ekiga, but cannot find documentation for the connection parameters. While Ekiga mainly works with twinkle I'd like to use linphone.

1 Answer 1

2

If you are using the ekiga user agent (UA) to register yourself with the ekiga.net sip server, the connection parameters are:

registrar: ekiga.net
username: <your username> (the bit before the "@ekiga.net")
password: <your password>

If you are using the linphone UA to register yourself with the ekiga.net sip server, the connection parameters are:

username: <your username> (the bit before the "@ekiga.net")
password: <your password>
domain: ekiga.net
(the transport MUST be UDP)

Note that if you are using the linphone UA (in fact, if you are using almost any UA other than the ekiga UA), the UA MUST be running on a machine with a public ip address. If your sip UA is running on a machine with a private ip address (i.e. if it's behind a standard domestic NAT router) then your UA's registration to the ekiga.net sip server WILL FAIL.

The reason for this failure to register from a private ip address is explained at https://jitsi.org/Documentation/FAQ#ekiga.net:

"The ekiga.net SIP servers are configured in a way that prevent Jitsi (and many other SIP user agents for that matter) to register with the service. Please use iptel.org or ippi.com instead.

Slightly Longer Answer: The service at ekiga.net is configured to only accept SIP REGISTER requests that contain a public IP address in their Contact header. This means that registration from Jitsi would fail unless you actually have a public IP address. The Ekiga client circumvents this by using STUN to learn the address and port that have been allocated for the current session."

tl;dr: if you want to receive voip calls using the linphone UA and you are, like most people, using a private ip address, sign-up for a free sip address from any one of:

  • getonsip.com
  • ideasip.com
  • iptel.org
  • linphone.org
  • opensips.com
  • sip2sip.info
  • sipgate.co.uk
0

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .