I want to use the bash syntax ${var/pattern1/pattern2} to replace the content of $var but for all matching patterns pattern1 instead of the first one.

$ A=aa 
$ echo ${A/a/b}

I want to get bb instead of ba.

1 Answer 1


You can try this syntax which gives output:

$ A=aa 
$ echo ${A//a/b}

${A//a/b} replaces all the matches of a with b. Whereas, ${A/a/b} will replace only 1st match of a.

More details about Bash Strings Manipulation can be found here.

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