Apparently I cannot count. I think there are three files in /media

$ tree /media
├── foo
├── onex
└── zanna
3 directories, 0 files

However, ls -l finds 12.

$ ls -l /media
total 12
drwxr-xr-x  2 root root 4096 Jul 31 20:57 foo
drwxrwxr-x  2 root root 4096 Jun 26 06:36 onex
drwxr-x---+ 2 root root 4096 Aug  7 21:17 zanna

And, if I do ls -la I get only . and .. in addition to the above, but the count is total 20

What's the explanation?


2 Answers 2


The 12 you see is not the number of files, but the number of disk blocks consumed.

From info coreutils 'ls invocation':

 For each directory that is listed, preface the files with a line
 `total BLOCKS', where BLOCKS is the total disk allocation for all
 files in that directory.  The block size currently defaults to 1024
 bytes, but this can be overridden (*note Block size::).  The
 BLOCKS computed counts each hard link separately; this is arguably
 a deficiency.

The total goes from 12 to 20 when you use ls -la instead of ls -l because you are counting two additional directories: . and ... You are using four disk blocks for each (empty) directory, so your total goes from 3 × 4 to 5 × 4. (In all likelihood, you are using one disk block of 4096 bytes for each directory; as the info page indicates, the utility does not check the disk format, but assumes a block size of 1024 unless instructed otherwise.)

If you want to simply get the number of files, you might try something like

ls | wc -l
  • 13
    ls | wc -l will fail if there are files with a newline in the filename. This is more resilient: find . -mindepth 1 -maxdepth 1 -printf . | wc -c
    – Flimm
    Commented Aug 10, 2016 at 19:18
  • 20
    "if file names have a new line in them" ... shudder
    – Petah
    Commented Aug 11, 2016 at 3:54
  • 8
    As man ls will tell you, you can avoid control chars with -b (escapes them) or -q (omits them). So for counting, ls -1q | wc -l is safe and accurate for showing non-hidden files. ls -1qA | wc -l to count hidden files (but not . and ..). I'm using -1 instead of -l because that should be faster.
    – Oli
    Commented Aug 11, 2016 at 15:24

user4556274 has already answered the why. My answer serves only to provide additional information for how to properly count files.

In the Unix community the general consensus is that parsing the output of ls is a very very bad idea, since filenames can contain control characters or hidden characters. For example, due to a newline character in a filename, we have ls | wc -l tell us there's 5 lines in the output of ls (which it does have), but in reality there's only 4 files in the directory.

$> touch  FILE$'\n'NAME                                                       
$> ls                                                                         
file1.txt  file2.txt  file3.txt  FILE?NAME
$> ls | wc -l

Method #1: find utility

The find command, which is typically used for working around parsing filenames, can help us here by printing the inode number. Be it a directory or a file, it only has one unique inode number. Thus, using -printf "%i\n" and excluding . via -not -name "." we can have an accurate count of the files. (Note the use of -maxdepth 1 to prevent recursive descending into subdirectories)

$> find  -maxdepth 1 -not -name "." -print                                    
$> find  -maxdepth 1 -not -name "." -printf "%i\n" | wc -l                    

Method #2 : globstar

Simple, quick, and mostly portable way:

$ set -- * 
$ echo $#

set command is used to set positional parameters of the shell ( the $<INTEGER> variables, as in echo $1 ). This is often used to work around /bin/sh limitation of lacking arrays. A version that performs extra checks can be found in Gille's answer over on Unix&Linux.

In shells that support arrays, such as bash, we can use

items=( dir/* )
echo ${#items[@]}

as proposed by steeldriver in the comments.

Similar trick to find method which used wc and globstar can be used with stat to count inode numbers per line:

$> LC_ALL=C stat ./* --printf "%i\n" | wc -l                                          

An alternative approach is to use a wildcard in for loop. (Note, this test uses a different directory to test whether this approach descends into subdirectories, which it does not - 16 is the verified number of items in my ~/bin )

$> count=0; for item in ~/bin/* ; do count=$(($count+1)) ; echo $count ; done | tail -n 1                                

Method #3: other languages/interpreters

Python can also deal with problematic filenames via printing the length of a list given my os.listdir() function (which is non-recursive, and will only list items in the directory given as argument).

$> python -c "import os ; print os.listdir('.')"                              
['file2.txt', 'file1.txt', 'FILE\nNAME', 'file3.txt']
$>  python -c "import os ; print(len(os.listdir('.')))"                    

See also

  • 2
    In bash, another option would be to use an array e.g. items=( dir/* ); echo ${#items[@]} (adding shopt -s dotglob to include hidden files). Commented Aug 11, 2016 at 4:01
  • 1
    Printing inode numbers makes it easy to filter hardlinks if desired, with find | sort -u | wc -l. Commented Aug 11, 2016 at 4:06
  • @steeldriver: I think the bash-array method is unlikely to be faster. If you want it to be recursive, you need to use items=( dir/** ) (with shopt -s globstar), but bash doesn't take advantage of extra metadata from readdir, so it stats every directory entry to see if it is a directory itself. Many filesystems do store the filetype in the directory entry, so readdir can return it without accessing the inodes. (e.g. the latest non-default XFS has this, and I think ext4 has had it for longer.) If you strace find, you'll see a lot fewer stat system calls than stracing bash. Commented Aug 11, 2016 at 4:11
  • 2
    Why not just use print(len(os.listdir('.')))? Fewer characters to type and also avoids accessing doubly-underscored attributes.
    – edwinksl
    Commented Aug 11, 2016 at 5:05
  • 1
    @edwinksl edited , thx Commented Aug 11, 2016 at 5:46

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