0
a=10.5
b=11.8
c=`expr $a + $b | bc`
echo $c

After execution, it's displaying an error message like non-integer argument. Why is this not performing arithmetic using expr?

  • 1
    To make a code block look nice, select the lines that should be in it and press the {} button. – Olathe Mar 25 '16 at 3:15
3

Explanation of errors

The error is the same as if you input:

$ expr 10.5 + 11.8
expr: non-integer argument

Expr is complaining that you gave it non-integers. This is because expr program was not designed for non-integer calculations:

Expr invocation:

Operands are either integers or strings.

  • expr was generated as standard error, your terminal just displays it
  • But when you use pipe |, pipe only transfers standard out, not standard error
  • Because bc did not receive anything to work with, it didn't give you any output at all, as you can see when you try sending nothing (except new-line) to bc:

    $ echo | bc
    

The result is bc says nothing. So what you see on your screen with your original command, was still just expr's complaint via standard error.

Recommendation

For decimal calculations, you can use just bc and some means to get input to bc, such as with here-strings:

$ bc <<< '10.5 + 11.8'
22.3

Or, to use variables:

$ a=10.5
$ b=11.8
$ c=$(bc <<< "$a + $b")
$ echo $c
22.3
  • The $( and ) is a command substitution
  • <<< string is a here-string syntax, sends the string contents to stdin, which bc receives
| improve this answer | |
1

info coreutils 'expr invocation' says:

16.4 `expr': Evaluate expressions
=================================

`expr' evaluates an expression and writes the result on standard
output.  Each token of the expression must be a separate argument.

   Operands are either integers or strings.  Integers consist of one or
more decimal digits, with an optional leading `-'.  `expr' converts
anything appearing in an operand position to an integer or a string
depending on the operation being applied to it.

However, you can use bc:

$ a=10.5 b=11.8 c=$(echo "scale=1;$a + $b" | bc -q );echo $c
22.3
| improve this answer | |
  • why c=` expr $a + $b | bc ` not working ? – Achal Mar 25 '16 at 2:31
  • Because it's expr 10.5 + 11.8 see above – waltinator Mar 25 '16 at 18:37

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.