I have about 260 files in a directory. How can I input these files one by one into some thing like this
file is an array name

file=input stream of multiple files 

tr -d '\r'  file2
rm $file
mv file2 $file
LOOP ends
  • You can do in-place edit, perl -i -pe 'tr|\r||d' files* and it is faster than repeated fork of tr command.
    – mpapec
    Jun 23, 2015 at 6:44
  • So basically you wanna delete all \r from each file in a directory ? Jun 24, 2015 at 9:37
  • Yes. That's what I want to do.
    – SamFlynn
    Jun 24, 2015 at 9:41

2 Answers 2


Using a find one-liner:

find . -maxdepth 1 -type f -exec sh -c '< "{}" tr -d "\r" > "{}.processed"' \;

This will create a carriage-returns-stripped copy of each file in the current working directory named as the original file with a .processed extension.

tr can read only from stdin, so it can't edit files in-place natively, however one hack is to redirect the content of a file to the stdin of a subshell and to redirect it as a here string to tr's stdin, so that the file is read before the truncation necessary in order to write the file takes place:

find . -maxdepth 1 -type f -exec bash -c '<<< "$(< {})" tr -d "\r" > {}' \;

Using perl

perl -i -pe 'tr/\r//d' <your_file>

and with find for all files in your folder:

  • long version

    find <your_path> -maxdepth 1 -type f -print0 | xargs -I{} -0 perl -i -pe 'tr/\r//d' {}
  • short version

    find <your_path> -maxdepth 1 -type f -exec perl -i -pe 'tr/\r//d' {} \;


$ printf "%s\n%s\n" "line 1" "line 2" > foo
$ printf "%s\r\n%s\n" "line 1" "line 2" > bar

$ hexdump foo
0000000 696c 656e 3120 6c0a 6e69 2065 0a32     

$ hexdump bar
0000000 696c 656e 3120 0a0d 696c 656e 3220 000a

$ perl -i -pe 'tr/\r//d' bar

$ hexdump bar
0000000 696c 656e 3120 6c0a 6e69 2065 0a32     

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