Run multiple line as a single line command bash

Question

Is there any way to run multiple line as a single line command in bash script.

This is my multiple line bash script

id=15;
if [ $id -ge 30 ]
then
echo Successful
echo $id
else
echo fail
echo $id
fi

I want to run this multiple line as a single line so far i have tried this way

id=15;if [ $id -ge 30 ]&&then&&echo Successful&&echo $id&&else&&echo fail&&echo $id&&fi

but when I executed this command in terminal i got this error

bash: syntax error near unexpected token `then'

Any idea how to change multiple line script to a single line command

Answer 1

Firstly you could replace the && with ; which is equivalent to the line breaks in your multiple-line code. Secondly I don't think you need the && (or ;) after the then statement.

The difference between the && and ; line breaks is that && will run the next block of code if and only if the previous block has executed properly.