How can I display the IP address shown on eth0 using a script ?


18 Answers 18


For the sake of providing another option, you could use the ip addr command this way to get the IP address:

ip addr show eth0 | grep "inet\b" | awk '{print $2}' | cut -d/ -f1
  • ip addr show eth0 shows information about eth0
  • grep "inet\b" only shows the line that has the IPv4 address (if you wanted the IPv6 address, change it to "inet6\b")
  • awk '{print $2}' prints on the second field, which has the ipaddress/mask, example
  • cut -d/ -f1 only takes the IP address portion.

In a script:

theIPaddress=$(ip addr show eth0 | grep "inet\b" | awk '{print $2}' | cut -d/ -f1)
  • this solution actually works! – thang Nov 14 '18 at 23:10
  • ip -4 ... and ip -6 ...! Thank you! – TamusJRoyce May 22 '19 at 18:12
  • ip addr show eth0 | grep -P "inet6?\b" | awk '{print $2}' | cut -d/ -f1 will print both IPv4 and IPv6. – Artem Russakovskii Jun 4 '20 at 8:14

Note: This answer is for older systems. If this does not work for you please consider other answers. This answer is not incorrect.

save this in a file and then run bash <filename>

ifconfig eth0 | grep "inet addr"

being more accurate to get only number showing IP address:

ifconfig eth0 | grep "inet addr" | cut -d ':' -f 2 | cut -d ' ' -f 1

Update: If this doesn't works for you, try the other answer

Update: For Ubuntu 18+, try: (don't forget to replace eth0 with interface you need the IP for. Thanks to @ignacio )

ifconfig eth0 | grep "inet " | awk '{print $2}'
  • 4
    of course this doesn't work in the latest ubuntu. the latest ifconfig returns "inet <ip>" instead of "inet addr <ip>" – thang Nov 14 '18 at 23:10
  • 2
    you can just use grep "inet" – Andrei Radulescu Nov 10 '19 at 15:11
  • here is an updated solution for ifconfig version "net-tools 2.10-alpha" : ifconfig eth0 | grep "inet" | grep -v "inet6" | sed -e 's/^[[:space:]]*//' | cut -d ' ' -f 2 – Maxime Ancelin Feb 13 '20 at 9:03
  • 1
    @MaximeAncelin you should add new answer for this – Edward Torvalds Feb 13 '20 at 9:57
  • 2
    quick update for Ubuntu 18.04: ifconfig wlan0 | grep "inet " | awk '{print $2}' – ignacio Oct 28 '20 at 16:55

Taken from https://stackoverflow.com/a/14910952/1695680

hostname -i

However that may return a local ip address (, so you may have to use, and filter:

hostname -I

From hostname's manpages:

-i, --ip-address

Display the network address(es) of the host name. Note that this works only if the host name can be resolved. Avoid using this option; use hostname --all-ip-addresses instead.

-I, --all-ip-addresses

Display all network addresses of the host. This option enumerates all configured addresses on all network inter‐faces. The loopback interface and IPv6 link-local addresses are omitted. Contrary to option -i, this option does not depend on name resolution. Do not make any assumptions about the order of the output.

  • 1
    for the record, I like ip addr show label 'enp*' better, but I is annoying parse, something like ip addr show label 'enp*' | grep -oP inet\ \\S+ | cut -d' ' -f2 can work... how pretty – ThorSummoner Nov 20 '18 at 23:37
  • ip route | grep default | grep -oP 'dev \S+' | cut -d' ' -f 2 | xargs ip addr show dev | grep -oP 'inet6? \S+' – ThorSummoner Apr 11 '20 at 1:43

@markus-lindberg 's response is my favourite. If you add -o -4 to ip's flags then you get a much more easily parsable (and consistent) output:

ip -o -4 a | awk '$2 == "eth0" { gsub(/\/.*/, "", $4); print $4 }'

-o stands for --oneline, which is meant to help in exactly this kind of situations. The -4 is added to limit to the IPv4 address, which is what all the other responses imply.

  • 1
    Love the ip flags. Using cut rather than advanced awk wizardry: ip -o -4 addr show eth0 scope global | awk '{print $4;}' | cut -d/ -f 1 – Dawngerpony Dec 16 '16 at 14:03
  • 1
    @DuffJ it's probably down to a matter of personal taste. I "discovered" cut way after I learned about awk, and I like minimising the number of commands on my pipelines. Nice suggestion in any case. – Amos Shapira Dec 17 '16 at 6:55
  • 1
    I completely agree, Amos. Thanks for your solution! – Dawngerpony Dec 19 '16 at 12:34
  • 1
    Very helpful. This should be the accepted answer, and this is not using the deprecated ifconfig which needs you to explicitly install net-tools in Ubuntu. – Haris Jun 11 '20 at 17:28

You should use ip (instead of ifconfig) as it's current, maintained, and perhaps most importantly for scripting purposes, it produces a consistent & parsable output. Following are a few similar approaches:

If you want the IPv4 address for your Ethernet interface eth0:

$ ip -4 -o addr show eth0 | awk '{print $4}'  

As a script:

$ INTFC=eth0  
$ MYIPV4=$(ip -4 -o addr show $INTFC | awk '{print $4}') 
$ echo $MYIPV4

The output produced above is in CIDR notation. If CIDR notation isn't wanted, it can be stripped:

$ ip -4 -o addr show eth0 | awk '{print $4}' | cut -d "/" -f 1  

Another option that IMHO is "most elegant" gets the IPv4 address for whatever interface is used to connect to the specified remote host ( in this case). Courtesy of @gatoatigrado in this answer:

$ ip route get | awk '{ print $NF; exit }'

As a script:

$ RHOST=  
$ MYIP=$(ip route get $RHOST | awk '{ print $NF; exit }')
$ echo $MYIP

This works perfectly well on a host with a single interface, but more advantageously will also work on hosts with multiple interfaces and/or route specifications.

While ip would be my preferred approach, it's certainly not the only way to skin this cat. Here's another approach that uses hostname if you prefer something easier/more concise:

$ hostname --all-ip-addresses | awk '{print $1}'  

Or, if you want the IPv6 address:

$ hostname --all-ip-addresses | awk '{print $2}'  

As a script:

$ MYV4IP=$(hostname --all-ip-addresses | awk '{print $1}') 
$ MYV6IP=$(hostname --all-ip-addresses | awk '{print $2}')
$ echo $MYV4IP 
$ echo $MYV6IP 

Here are some oneliners.....


ifconfig eth0 | awk '/inet addr/{split($2,a,":"); print a[2]}'

split function in the above awk command splits the second column based on the delimiter : and stores the splitted value into an associative array a. So a[2] holds the value of the second part.


ifconfig eth0 | sed -n '/inet addr/s/.*inet addr: *\([^[:space:]]\+\).*/\1/p'

In basic sed , \(...\) called capturing group which is used to capture the characters. We could refer those captured characters through back-referencing. \([^[:space:]]\+\) captures any character but not space one or more times.


ifconfig eth0 | grep -oP 'inet addr:\K\S+'

\K discards the previously matched characters from printing at the final and \S+ matches one or more non-space characters.


ifconfig eth0 | perl -lane 'print $1 if /inet addr:(\S+)/'

One or more non-space characters which are next to the inet addr: string are captured and finally we print those captured characters only.

  • @edwardtorvalds added some explanation. I think this would be helpful for future readers. Feel free to ask any questions from the above commands... :) – Avinash Raj Dec 12 '14 at 8:07
ip addr|awk '/eth0/ && /inet/ {gsub(/\/[0-9][0-9]/,""); print $2}'

This only use ip addr which is a replacement for ifconfig and awk combined with substitution (gsub).

Stop using too many processes for simple tasks


Just one more option that can be useful if you don't have awk (as it is the case in some embedded devices):

ip addr show dev eth0 scope global | grep "inet\b" | cut -d/ -f 1 | egrep -o "([[:digit:]]{1,3}[.]{1}){3}[[:digit:]]{1,3}"

Here's a good one, only uses grep as secondary command:

ip addr show eth0 | grep -oP 'inet \K\S[0-9.]+'

I don't see why you should use more commands than needed


ifconfig eth0|grep 'inet '|awk '{print $2}'


here's for IPv4:

ip -f inet a|grep -oP "(?<=inet ).+(?=\/)"

here's for IPv4 & particular dev (eth0):

ip -f inet a show eth0|grep -oP "(?<=inet ).+(?=\/)"

for IPv6:

ip -6 -o a|grep -oP "(?<=inet6 ).+(?=\/)"


I suggest using a python library like netifaces that is specifically designed for this purpose.

sudo pip install netifaces
python -c "import netifaces; print netifaces.ifaddresses('eth0')[netifaces.AF_INET][0]['addr']"

To obtain the default network interface that is in use.

default_inf = netifaces.gateways()['default'][netifaces.AF_INET][1]

this can be used with a normal user too.

ip addr show eth0 | grep "inet " | cut -d '/' -f1 | cut -d ' ' -f6
  • he ask for eth0, this version of your script could help (also show loopback tho) ip addr show | grep "inet " | cut -d '/' -f1 | cut -d ' ' -f6 – TiloBunt Mar 25 '17 at 17:01
  • This is pretty much the same answer as askubuntu.com/a/560466/367990, just using cut twice instead of a combination of awk and cut to parse the output. Next time you should better check out all other answers first and ensure you don't post a duplicate solution. In this case here, I think it's arguable whether it's a duplicate or just similar, so please take it as a general hint. Thanks. – Byte Commander Jul 7 '17 at 19:49

Yet another way (assuming you don't want a CIDR address and want IPv4):

$ ip -br -4 addr show dev eth0 | awk '{split($3,a,"/"); print a[1]}'
  • Uses the ip command which is not deprecated
  • Uses only one command for filtering

This is the shortest way I could find:

ip -f inet addr show $1 | grep -Po 'inet \K[\d.]+'

Replace $1 with your network interface.

ip -f inet tells ip to only return values for the inet (ipv4) family.

grep -Po tells grep to interperate the next value as a perl-regex, and only print the matching values.

The regex \K[\d.]+ says "throw away everything up to this point (\K), and match as many numeric values followed by a dot in a row as possible". This will therefore only match the IP address and ignore everything after it, including the shortform \XX subnet mask.


in these days with multiples interfaces (eg if you use a docker) and naming interface by ETH is not anymore the norms

I use this command to extract the IP/Mask :

IPMASK=$(ip a s|grep -A8 -m1 MULTICAST|grep -m1 inet|cut -d' ' -f6)

So whatever how many interfaces I'll have and whatever their name, GREP will only grab the first having the MULTICAST option.

I use this command to extract only the IP without the mask :

IP=$(ip a s|grep -A8 -m1 MULTICAST|grep -m1 inet|cut -d' ' -f6|cut -d'/' -f1)

I use these command on different BDS & NIX it never fail ;)

  • If you're going to parse the output of ip, use the -o option. – muru Oct 26 '17 at 8:31

In my script I'm using something like that:

if [[ $(ip addr show eth0) =~ $re ]]; then
    echo ${BASH_REMATCH[1]}
    echo "Cannot determin IP" 1>&2

It doesn't spawn any process.


If eth0 has multiple IPs and you are looking for a public one here is an example of ignoring the 2 most common internal IP address ranges.

ip -4 addr show eth0 | grep -oP '(?<=inet\s)\d+(\.\d+){3}' | grep --invert-match -P '^(10\.|192\.168\.)'

This ignores and IPs.

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