-1

A. I used the following code to get the modified date of a file. But this is also selecting the subdirectories and thus returning an error. How can I fix this?

for file in $1/*; do
        echo `stat -c %y $file | cut -d ' ' -f1`
done

$1 is the directory I am passing.

B. Also is there any way to do this thing. That I need to pass a directory and date range as command-line argument and list the file and modified date which lies in this date range.

Eg output.sh /home/user/desktop 2014-10-07 2014-11-17 should list all the files in this directory which are modified in this time interval.

closed as off-topic by muru, Gilles, Mitch Nov 12 '14 at 12:39

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0

Regarding part A of your question, here is a reference to the standard file tests.

In particular, what you can do is:

for file in $1/*; do
    [ ! -d "$file" ] && echo `stat -c %y $file | cut -d ' ' -f1`
done

As for part B, see this stackoverflow question.

0

For part A, a more efficient approach:

find $1 -maxdepth 1 ! -type d -exec stat -c "%y" {} + | cut -d' ' -f1

find is excellent at filtering out based on type, and exec with + should run far fewer stat process. Piping the whole output to cut means we have to run cut only once. And there is really no need to do

echo `some command`

The only benefit is converting multi-line output to single line, which is not applicable to your case anyway.

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