I'm pretty new to bash scripting. I'm trying to make a script to export the http_proxy variables. This is what I do from the terminal:

$export http_proxy=http://proxy21.iitd.ernet.in:3128/
$export https_proxy=https://proxy21.iitd.ernet.in:3128/

This works just fine. Now, here's my script (called setproxy):

#!/usr/bin/env bash
if [ $1 -eq 22 ]
    export http_proxy=http://proxy22.iitd.ernet.in:3128/
    export https_proxy=https://proxy22.iitd.ernet.in:3128/
elif [ $1 -eq 21 ]
    export http_proxy=http://proxy21.iitd.ernet.in:3128/
    export https_proxy=https://proxy21.iitd.ernet.in:3128/
elif [ $1 -eq 61 ]
    export http_proxy=http://proxy61.iitd.ernet.in:3128/
    export https_proxy=https://proxy61.iitd.ernet.in:3128/
elif [ $1 -eq 62 ]
    export http_proxy=http://proxy62.iitd.ernet.in:3128/
    export https_proxy=https://proxy62.iitd.ernet.in:3128/

Essentially, I want to set the appropriate proxy server depending on the input. I put it in the bin folder, made it executable, added bin to the path, logged in and out. The terminal accepts setproxy as a valid command (at leat there's no command not found error) But, when I do:

$setproxy 22

There is no effect. The proxy remains unchanged. What am I doing wrong?


1 Answer 1


When you call the script, a new child shell is invoked to run it. Its proxies are set, but the proxy of the parent process (your shell) can't be changed from a child process. Try sourcing the script, i.e. call it like

. setproxy 21

Then the script will be interpreted by your current shell.

  • That worked. Thanks! Is there any way to avoid the . at the start? Aug 26, 2014 at 10:40
  • The . is what makes it work.
    – choroba
    Aug 26, 2014 at 10:42
  • Oh, ok. One more thing, how can I set the system wide proxy (ie, the one when I do Network -> Network Proxy -> (Set the proxy) -> Apply System wide) Aug 26, 2014 at 10:45

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