End script and restart it with the same options and arguments

Question

Usually !! repeats the last given command. But it doesn’t seem to work in a bash script. Is there a way to end a script and repeat it with the exact same options and arguments given the last time?

Additional info: In a part of my script it is checked if a server is running. If it isn't, it is started by etherwake. This is the part, where I want the script to be ended and restarted, until the server is finally up. Ignoring the problem that this easily can lead to a endless loop which might threaten system/network stability.

Is there an easier/safer way? There doesn't seem to be a GOTO LINE command or something similar.

Answer 1

Just make an infinite while loop:

#!/bin/sh

while [ TRUE ]; do

check_server_status 10.0..
etherwake ff:ff..

done

Answer 2

How about

while server-is-not-running; do
    try-and-start-server
    sleep seconds-to-wait
done

where

• server-is-not-running is your current test to see if the server is running, i.e. a shell function or an external command returning non-zero if the server is running (alternatively, ! server-is-running if that function or command returns zero if the server is running).
• try-and-start-server is the command to start the server, which again can be a shell function or external command
• seconds-to-wait is a sensible number of seconds to wait for successful start

To limit the number of attempts, replace the while with a for:

for i in {1..number-of-attempts}; do
    try-and-start-server
    sleep seconds-to-wait
    server-is-not-running || break
done