1

I am trying to output the values of array element but I am getting weird output. Please have a look at it and help me solve it. Thank you.

n=2
declare -a myarray[$n]
myarray[0]=hey
myarray[1]=hello
myarray[2]=bye
for i in ${myarray[@]}
do
        echo $i
done

Output:

robin@robin-VirtualBox:~/lx$ sh array.sh
array.sh: 2: array.sh: declare: not found
array.sh: 3: array.sh: myarray[0]=hey: not found
array.sh: 4: array.sh: myarray[1]=hello: not found
array.sh: 5: array.sh: myarray[2]=bye: not found
array.sh: 6: array.sh: Bad substitution
1

declare is a bash shell builtin, and is not defined in the sh shell.

So, you must to run your script using the following command:

bash array.sh

Or add, the following shebang line at the start of your script:

#!/bin/bash

Be sure that your script is exectutable:

 chmod +x array.sh

And run it using the following command:

./array.sh
2

Your script is correct, but type:

./array.sh

instead of sh array.sh

The difference between ./ and sh is explained here.

  • i'm getting permision denied. I even tried with sudo. – Robin Apr 27 '14 at 0:08
  • Its ok, I had to make it executable. Thank you. – Robin Apr 27 '14 at 0:10

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