59

Is there a way to get absolute path of a file that is being searched?

For example:

find .. -name "filename"

It gives me results like ../filename but I want the full path.

What I need is to find in the parent directory and its children, for a specific file, that I will use in another script later.

Thanks

1
39

You can use bash's Tilde Expansion to get the absolute path of the current working directory, this way find prints the absolute path for the results as well:

find ~+ -type f -name "filename"

If executed in ~/Desktop, this is expanded to

find /home/yourusername/Desktop -type f -name "filename"

and prints results like:

/home/yourusername/Desktop/filename

If you want to use this approach with the current working directory’s parent directory you need to cd before calling find:

cd .. && find ~+ -type f -name "filename"
0
27

Try something like:

find "$(cd ..; pwd)" -name "filename"
9
  • Thanks, I was just testing $(cd ..; pwd). Here it works OK, but if I do it alone in a Terminal, I can't get the parent dir... I get "Bash: <dir>: Is a directory. And if I do $(cd ..; echo "something") I get "something: not a command"
    – JorgeeFG
    Apr 7 '14 at 15:52
  • Do you mean like a separate command? Then you would need to leave out the dollar sign: (cd ..; pwd) Apr 7 '14 at 15:53
  • 1
    Yes ( ... ) means execute in a subshell, the output gets written to stdout. $( ... ) stands for "command substitution". The latter can be used as if it were a variable expansion. Apr 7 '14 at 16:03
  • 2
    @Scrutinizer - I think you misunderstand how find works. If you use the full path in your search, you get the full path in your output. find /home/your_user -name foo. As OP is using "../" , hard to guess the full path to give in an answer.
    – Panther
    Apr 8 '14 at 13:02
  • 2
    @JorgeeFG $(builtin cd ..; pwd) will canel functions, aliases.
    – bac0n
    Oct 16 '19 at 17:37
21

Try using the -exec option of find:

find .. -name "filename" -exec readlink -f {} \;

Note: readlink prints the value of a symbolic link or canonical file name.

2
  • 1
    this will call readlink on every file so it will be very ineffective.
    – bac0n
    Oct 16 '19 at 18:20
  • I like the simplicity of this solution but I found xargs to be much faster.............................................. find .. -name "filename" | xargs readlink -f Nov 13 '20 at 16:39
17

The simplest way is

find "$(pwd -P)" -name "filename"
2
  • 1
    Yes! Or find `pwd -P` -name "filename" Jul 24 '19 at 0:35
  • 1
    this will find files in the current directory not from parent.
    – bac0n
    Oct 16 '19 at 18:21
5

This worked for me, but will only return the first occurrence.

realpath $(find . -type f -name filename -print -quit)

To get full paths for all occurrences (as suggested by Sergiy Kolodyazhnyy)

find . -type f -name filename | xargs realpath
3
  • Previous comment removed, +1, good job @Wyrmwood Oct 16 '19 at 20:51
  • Exactly what I needed (just the first occurrence and to print the full path including the filename in the output. Thank you Sir Apr 3 '20 at 18:09
  • 1
    this doesn't work for files with whitespaces
    – peixotorms
    May 21 '20 at 11:19
1

Also using PWD can show you the full directory. Pwd will show you all your directorys you are in like the expanding of filename. Hope this helped.

1

Removing last directory component with parameter Expansion.

find "${PWD%/*}" -name 'filename'

An example of how you can use mapfile to save output from find to an indexed array for later use.

mapfile -t -d '' < <(find ${PWD%/*} -name 'filename' -print0)

(if no array name is specified, MAPFILE will be the default array name).

for i in "${MAPFILE[@]}"; do
    echo "$((n++)) $i"
done
0

Try this way:

find $PWD -name "filename"
0

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