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How would I delete all files in a directory and its subdirectories that do not end with -out? For instance delete foo.bar but do not delete foo-out.bar.

EDIT:

I have tried

for a_file in $(find .  ! -name '*-out*'); do rm  $a_file; done;

But this script doesn't incorporate spaces. How would I fix that?

2

How about using the find command's built-in -delete action? that should be whitespace safe

find . ! -name '*-out*' -type f -delete

Otherwise, you could do a null-terminated while loop - make sure you quote the filename variable as well

while read -rd $'\0' f; do rm "$f"; done < <(find . ! -name '*-out*' -type f -print0)
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0

In addition to the answer.

You don't have to use a for loop. find provides -exec and -delete.

A quick test

cd `mktemp -d`
touch {1..9}\ -out{a..c}
$ find . -name '*-out*'
./2 -outb
./8 -outb
./9 -outa
./4 -outc
./6 -outb
./5 -outc
./7 -outb
./9 -outb
./2 -outa
./4 -outa
./8 -outc
./8 -outa
./7 -outc
./3 -outb
./6 -outa
./3 -outa
./1 -outb
./9 -outc
./1 -outa
./5 -outa
./4 -outb
./3 -outc
./1 -outc
./5 -outb
./2 -outc
./7 -outa
./6 -outc

It works with spaces.

What you need is:

find . ! -name '*-out*' -exec rm -f {} \;

A safer alternative: find . -name '*-out*' -exec rm -i {} \;

NOTE: use -exec rm -i {} \; to confirm deletion.

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