6

Can someone tell me how to find out which python script is using lots of system resources?

I can see with the 'top' command that a process called "python" is always near the top of the list.

2603 jesse     20   0  159m  27m  13m S    6  1.4   1:47.74 python

Can someone tell me how to find this specific python script's name?

I could go through the arduous process of disabling startup apps/processes until I finally found the one that starts this python process but there must be a better way of determining what exactly this python process is, yes?

Doing a ps -AH doesn't yield anything useful.

ps -AH

   1 ?        00:00:00 init
...
1325 ?        00:00:00   lightdm
1382 tty7     00:01:57     Xorg
2265 ?        00:00:00     lightdm
2510 ?        00:00:00       gnome-session
2546 ?        00:00:00         ssh-agent
2560 ?        00:00:02         gnome-settings-
2582 ?        00:00:01           syndaemon
2578 ?        00:00:49         compiz
3009 ?        00:00:00           sh
3010 ?        00:00:01             gtk-window-deco
2590 ?        00:00:00         nm-applet
2591 ?        00:00:00         bluetooth-apple
2592 ?        00:00:00         indicator-ubunt
2593 ?        00:00:00         gnome-fallback-
2600 ?        00:00:05         nautilus
2601 ?        00:00:00         everpad
2603 ?        00:02:24         python
8

I've found the answer myself!

It's

ps -Ao pid,cmd
  • -A = Show All Processes
  • -o pid,cmd = display options: process id, full command string

Adding -H gives you a tree listing so you can see which process started which other process.

ps -AHo pid,cmd

Turns out for me the process in question was /usr/share/screenlets/screenlets-pack-basic/Sysmonitor/SysmonitorScreenlet.py

I think I'll turn off that sysmonitor screenlet since it constantly polls the CPU and uses more memory than than the entire rest of the desktop.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.