I have a folder with quite a few files in it. I want to display the following:
filename_1
first line of file1
second line of file1
third line of file1
filename_2
first line of file2
second line of file2
third line of file2
filename_3
first line of file3
second line of file3
third line of file3
etc. How can I do that?
You use the head command to do this, with the -n argument with the number of lines from each file, like this:
head -n3 *
or
head -n3 *.txt
This also works for a single file:
head -n3 filename.txt
head version head (GNU coreutils) 8.5 it by default will. Or maybe you're using an alias head --quiet?
head
You use head with the -n option.
head -n 10 FILE
This will print the first ten lines of a file.
Another useful variation would be -n -NUMBER.
head -n -10 FILE
This will print all but the last ten lines of a file.
To solve your problem and get your desired output you can do the following.
basename * && head -n NUMBER *
or
basename *.FILETYPE && head -n NUMBER *.FILETYPE
This will get you following output:
FILENAME
LINE ONE
LINE TWO
LINE THREE
This will do what you want, hopefuly:
find . -print -exec head {} -n 3 \;
-print will show the filename and the rest (from -exec) will show the first 3 lines of each file
Change the number according to your needs...
To add the filename to the head output use 'head -v'. So 'head -vn 3 *.html' gives me:
# head -vn 3 *.html
==> WebInfo.html <==
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
==> convert.html <==
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
==> misc.html <==
<html>
<head>
<title>WIP</title>