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Not sure if it was asked before but I really couldnt find anything related to this. Heres my Question. Opening a URL in firefox through linux command line works fine, like below:
firefox www.google.com
But, how do I open a URL having GET params, e. g.:
firefox www.google.com?param1=val1
It URL Encodes the whole URL and converts the ? to %3F.
On window open, the URL becomes: www.google.com%3Fparam1=val1 and not understood by the browser.
If you type that from a command prompt then the shell will parse the ?
(The same will happen if your URL contains an ampersand (&) or an asterix (*).
To avoid this use double quotes around the part you do not want the shell to parse.
E.g.
/usr/local/bin/firefox "http://www.google.com?param1=val1"
Please check the result of file `which firefox`,and check if it is a script file, not a executable file. If it's a script file, then it would be very likely that it doesn't quote the arguments correctly.
We had the same problem. The answer for us was to fully-qualify the url, including the http:// part.
For example, this works:
firefox http://www.google.ch?q=fred
firefox "www.google.com?param1=val1"