How can I automatically shutdown the system after a certain customizable time?
5 Answers
Open a terminal window and type in:
sudo shutdown -h +60
and just replace 60 with whatever number of minutes you want to take.
More info here:
http://ubuntuforums.org/archive/index.php/t-473173.html http://www.linux.org/lessons/beginner/l5/lesson5a.html
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shutdown +m 60 doesn't work for me. gives me an error message and says that there's an invalid time value.– NESJan 3, 2011 at 14:26
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I thought it was odd... it shouldn't be "+m 60", it should be "+60" (or maybe more like "-h +60". The bottom of this page seems to know how it works: linux.org/lessons/beginner/l5/lesson5a.html.– DanielJan 3, 2011 at 19:04
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"shutdown -P 1" - works well and shuts down the system in 1 minute, no time unit needed.– n3rdAug 2, 2011 at 12:01
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2i didn't down vote. But Gshutdown doesn't work smoothly here. When i choose shutdown it insteads log the user out?– NESJan 3, 2011 at 14:45
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Because the topic abt shutting down PC after certain period of inactivity is redirected to this topic, I will explain this issue here.
I spent lots of time to solve this problem, so I find it useful to share it, to make the same issue simple for others. I hv tried different programmes but they haven't work for me so I found using short script with cronjob the best solution.
Firstly I refered to post Timed Shutdown - shutdown after 30 minutes
I will copy it below and then explain improvements to make it work:
Install xprintidle. This tool gives the idle time of a user.
sudo apt-get install xprintidle
Make a script autoshutdown.sh which checks for the idle time and instructs the computer to shutdown if idle for 30 minutes.
idle=$(xprintidle) if [ $idle -gt 1800000 ]; then shutdown -h now fi
Make a cronjob for this that checks from time to time if the system has been idle for too long and if it has been idle for a longer than 30 minutes it will shutdown. Note that the cronjob has to be made for the root user.
This script needs some improvements to work, like:
idle=`env DISPLAY=:0 su OUR_USER -c xprintidle 2>&1`
OUR_USER
is the user we refer to for checking idle time (not root user)
DISPLAY=:0
is correct for one desktop display (run env
command to read DISPLAY
in your situation)
if script is run by OUR_USER
, line above can be reduced:
idle=`env DISPLAY=:0 xprintidle 2>&1`
This topic is described http://ubuntuforums.org/showthread.php?t=1069602
if script is run by OUR_USER
, shutdown
command should be preceded by sudo
sudo shutdown -h now
My script was run from cron by line in cron file:
*/5 * * * * /home/OUR_USER/autoshutdown.sh
- every 5 minutes
- OUR_USER should be replaced as earlier to the user we refer to.
If script is not run by root we should remember to add the line:
ALL ALL=(ALL) NOPASSWD: /sbin/shutdown
in sudoers file, so shutdown command won't need a password to be executed.
I tried such cronjobs on 2 similar distro Lubuntu 12.04.4 RC LXLE 32-bit ( http://www.lxle.net/ )
In one system it works only using root cronjob set in file:
/var/spool/cron/crontabs/root
CAVEAT
Another problem is that xprintidle in my system has given sometimes random for me values and sometimes logically incremental. The final result - my system has been usually shutdown after 20 mins maybe, if I set the max idle value to 30 mins. I think the culprit is xscreensaver which doesn't work as is set by entered parameters.
You can use
ComplexShutdown https://launchpad.net/complexshutdown
or EasyShutdown https://launchpad.net/easyshutdown
You can use sleep
for that. They're used to delay/ pause an operation. Combine that with shutdown
you get a power off timer.
Example to sleep after 1 hour:
sleep 3600 && sudo shutdown now
You can use math as well, here's to power off after 3 hour:
sleep $((3600*3)) && sudo shutdown now