How to run a program as a service (silent)?

Question

I have a python based server which i start from the terminal. This particular instance of the terminal then gives control to the program, and the program uses it as a kind of logging window, until its closed. Is this normal, or should i somehow try to start the program some other way in which it will simply show as an active process? If i close the terminal from which i started the program, the program dies with it.

Thank you

Answer 1

Turn it to a daemon (service)
daemon --name="yourservicename" --output=log.txt sh yourscript.sh

Answer 2

Even old bash is using & for sending processes to background, but there is few other ways too .. but basic two are these :

1.)$~ your_command > outputfile_for_stdout &
        # runs your command in background, giving you only PID so you can exit that process by `kill -9 PID_of_process`
        # & goes at the end of row      


2.)$~ your_command > outputfile_for_stdout 
        # this will run your program normally
        # press  Ctrl + Z then program will pause
   $~ bg
        # now your program is running in background
   $~ fg
        # now your program came back to foreground
3.)you can run terminal window under screen command so it will live until you either kill it or you reboot your machine
   $~ screen
   $~ run_all_your_commands
       # Ctrl + A + D will then detach this screen
   $~ screen -r will reattach it

---

Some other useful commands :

   $~ jobs
        # will show you all processes running right now, but without PID
   $~ ps
        # will show you all processes for actual terminal window

Answer 3

$ servicename &

Using & causes the program to run in the background, instead of blocking the shell until the program ends.

Answer 4

You can also use:

start-stop-daemon -SbCv -x your_command

here is init.d script to start and stop a program in the background.

Answer 5

From the terminal you could also run screen or follow up you command with &. Easy way to run continuous processes.