Count number of files with specific extension(s) for each subdirectory

Question

Source: Any directory tree with any number and type of files. Q: How many .jpg or .jpg and .png (for example) are in each subdirectory?

How can I limit the code below for files with 1 or more specific extension(s)? Having trouble inserting the -type f -name "*.jpg*", for example.

for DIR in $(find . -maxdepth 99 -type d)
do
    printf "%10d\t%s\n" $(find ${DIR}|wc -l) "${DIR}" 
done

Desired output:

118   ./aaa
 73   ./aaa/bbb
 16   ./aaa/bbb/ccc

If more than one file types are counted, then their combined total number in each subdirectories should be displayed.

Answer 1

Probably this find|xargs solution will work as you need.

find . -mindepth 1 -maxdepth 99 -type d -print0 | \
xargs -0 -i bash -c 'printf "%10d\t%s\n" "$(find "$1" -maxdepth 1 -type f -regextype awk -iregex ".*\.(jpg|jpeg|png)" | wc -l)" "$1"' - '{}'

Some explanations:

• The -mindepth 1 option is added in order to skip the current directory and process only the sub directories.
• The -print0 provides the output entries with null delimiter, it works together with the -0 option of xargs.
• The option - "{}" at the end will pass the xargs argument as value of the first positional parameter $1 of the bash command.
• Within the second find command -iregex means case insensitive regular expression (you could use -regex instead).

Answer 2

Here's from mine, modified from this answer.

find . -maxdepth 100 -type d -print0 | while read -d '' -r dir; do count=$(find "$dir" -maxdepth 1 -type f \( -name '*.jpg' -o -name '*.png' \) -ls | wc -l); printf "%5d %s\n" "$count" "$dir"; done

Return this on my test directory.

20 .
11 ./level2
3 ./level2/level3

Where the content is:

$ tree -L 3 level1/
level1/
├── 1.png
├── 10.png
├── 11.png
├── 12.png
├── 13.png
├── 14.png
├── 15.png
├── 16.jpg
├── 17.jpg
├── 18.jpg
├── 19.jpg
├── 2.png
├── 20.jpg
├── 3.png
├── 4.png
├── 5.png
├── 6.png
├── 7.png
├── 8.png
├── 9.png
└── level2
    ├── 20.jpg
    ├── 21.jpg
    ├── 22.jpg
    ├── 23.jpg
    ├── 24.jpg
    ├── 25.jpg
    ├── 26.png
    ├── 27.png
    ├── 28.png
    ├── 29.png
    ├── 30.png
    └── level3
        ├── bull_city.png
        ├── man_city.png
        └── newyork_city.png

2 directories, 34 files

---

Just realized you only need sub directories printed.

find . -mindepth 1 -maxdepth 100 -type d -print0 | while read -d '' -r dir; do count=$(find "$dir" -maxdepth 1 -type f \( -name '*.jpg' -o -name '*.png' \) -ls | wc -l); printf "%5d %s\n" "$count" "$dir"; done

Return this.

11 ./level2
3 ./level2/level3

Answer 3

Find has logical operators like AND, NOT and OR.

To specify more than one extension to search for you need to put the arguments in parentheses, as well as escape the parentheses to avoid them being processed by bash:

find . \( -type f -name "*.jpg" -o -name "*.png" \)