bash pipe multiple outputs as input to other command

Question

I am noob with shell script and I am trying to pass multiple arguments to an command. I have a urls.txt file that looks as below

name1,http://url1
name2,http://url2
name3,http://url3
name4,http://url4

with the below command I am able to get output after splitting by comma

cat urls.txt | cut -d ',' -f1
cat urls.txt | cut -d ',' -f2

The first one gives the name1, name2, etc and second one gives http://url1 http://url2. what I wanted to do was pipe both of them as a variable to a third command where I can use both of them.

Any ideas or suggestions are highly appreciated?

Answer 1

$ while IFS=, read nam url ;do echo "name:$nam, url:$url" ; done <urls.txt 
name:name1, url:http://url1
name:name2, url:http://url2
name:name3, url:http://url3
name:name4, url:http://url4