When I open a RAM-intensive app (VirtualBox set at 2GB of RAM), some swap space is generally used, depending on what else I have open at the time.

However, when I quit that last application, the 2GB of RAM is freed up, but the same swap space use remains.

For example, right now, about two hours after having closed VirtualBox, I have 1.6GB free RAM and still 770MB in swap.

How can I tell Ubuntu to stop using that swap and to revert to using the RAM?

  • 1
    The easiest thing reboot your device and save time of coping to ram and free ram save power of laptop and cpu temperature Commented Jun 13, 2016 at 4:18
  • 9
    Big assumption that repopulating all the stuff on your computer takes less time than that.
    – Jono
    Commented Apr 24, 2017 at 18:06
  • 3
    Ubuntu 16.04, at least, can keep using swap long after it was needed thusly making your system orders of magnitude slower by relying on the swap file even though no longer a necessity. The manual intervention can therefore by useful. Rebooting is not always an option.
    – matanox
    Commented Mar 14, 2019 at 9:24

8 Answers 8


The Linux kernel underlying Ubuntu will automatically "swap in" those pages from disk to RAM as needed, so in general I'd say just let it happen naturally.

However, if you really feel that you need to force it, (I can see a scenario where you would want to know the system will be responsive later) you can momentarily disable and re-enable swap

sudo swapoff -a
sudo swapon -a

OR alternatively as a single line

sudo swapoff -a; sudo swapon -a

Be careful doing this, as you may make your system unstable, especially if its already low on RAM. Be sure to have enough free RAM in your system, or you might not be able to free the swap and the OOM-Killer would end up killing some of your processes.

Note that the swapoff may take a while. This is particularly true if you have lot of swap to be swapped off.

  • 11
    That did the trick, the swap was copied to ram. I guess you just need to make sure to have at least the amount of swap used as free ram before running swapoff, right?
    – jfoucher
    Commented Aug 6, 2010 at 8:22
  • 13
    The swap was not copied to RAM. It was merely disabled. You should ensure the box is not swapping before doing this. If you do, then the kernel will see the memory disappear and the OOM-Killer will probably start killing off applications arbitrarily. There's no reason you should need to 'clean' out the swap like this. (see my other comment) :)
    – popey
    Commented Aug 6, 2010 at 10:06
  • 71
    Actually the swap is, basically, copied to ram, or more accurately, the pages are swapped back in from disk to RAM before the swap can be disabled.
    – SpamapS
    Commented Aug 7, 2010 at 15:00
  • 16
    The pages are copied to RAM only if they are still needed by some process. Sometimes a swapped page belongs to a process that has already been finished, and the kernel doesn't care to remove these pages from swap immediately. Commented Dec 30, 2013 at 14:57
  • 11
    This should be the correct answer, as it is the way to get the swapped pages back to RAM and then empty the swap memory Commented May 5, 2016 at 8:58

Just because swap is allocated, doesn't mean it's being 'used'. Whilst programs like system monitor and top will show some of your swap space being allocated (in your example 770MB) that doesn't mean that the system is actively swapping in/out.

To find out if anything is swapping in/out you can use the vmstat command. Leave it running a few seconds to settle down and watch the si (swapin) and so (swapout) columns. If nothing is happening then there is no reason to be concerned.

Here's the output of running vmstat 1, where you can see my machine is not swapping at all.

procs -----------memory---------- ---swap-- -----io---- -system-- ----cpu----
 r  b   swpd   free   buff  cache   si   so    bi    bo   in   cs us sy id wa
 0  0  78588 230788   9596  72196    0    0     0     0  543  652 12  6 78  0
 0  0  78588 230780   9596  72196    0    0     0     0  531  410  1  0 99  0
 0  0  78588 230796   9596  72196    0    0     0     0  300  335  1  1 97  0
 1  0  78588 230788   9608  72224    0    0    40     0  737  762  4  4 84  8
 5  0  78588 230788   9608  72224    0    0     0     0  415  385  9  3 84  0
 0  0  78588 230540   9616  72224    0    0     0    44  611  556 55  5 31  0
 0  0  78588 230532   9616  72224    0    0     0     0  574  662  1  6 89  0

Yet here in top you can see I have swap space allocated:-

Mem:    475236k total,   245076k used,   230160k free,     9720k buffers
Swap:   491512k total,    78588k used,   412924k free,    72476k cached
  • 54
    “no reason to be concerned”, up to the point when I continue to use some application that was swapped out. then all hell breaks loose. Commented May 13, 2014 at 12:14
  • 292
    This post doesn't answer the question. Commented Jun 25, 2014 at 20:45
  • 23
    The premise of the question is based on misconceptions. This post addresses the misconceptions.
    – popey
    Commented Jun 26, 2014 at 10:11
  • 52
    I don't see a misconception, I see a disagreement about what "used" means. You are meaning "used" to refer to actively swapping in/out, while the original question appears to be posed with "used" meaning that there is data that has been swapped out, which may later need to be swapped back in. There are valid reasons to want to flush the swap after an event that swaps out a lot of other memory, essentially pre-empting the active swapping that the user knows will occur later (especially if the later 'de-swapping' is likely to occur while the disk is under load for other reasons). Commented Oct 10, 2014 at 2:09
  • 56
    After running a memory intensive application, my other applications are unrepsonsive when I switch to them, presumably due to being swapped. Some way of telling the system to un-swap as much data as possible (followed by a coffee break) would be better than having to wait 20s every time I Alt+Tab. Commented Nov 1, 2014 at 11:18

You can also set your "swappiness" value from the default of 60, this way the swap won't grow so large to begin with. Why the shipping default is set to 60 when the recommended value is 10 perplexes me. From the Ubuntu SwapFAQ:

The default setting in Ubuntu is swappiness=60. Reducing the default value of swappiness will probably improve overall performance for a typical Ubuntu desktop installation. A value of swappiness=10 is recommended, but feel free to experiment.

By changing this value to 10 or even 0, you can add a significant and perceivable speed boost to an older system with a slow drive. Setting this value to 0 does not turn swap off for Linux kernel 3.4 and below but with 3.5+ it does so you will want to use a value of 1 if you want to keep it on its lowest setting*.

I see no reason not to set this to 0 since anything that hits disk is slower than RAM. I have 8 virtual cores, a fast SSD & 8 GB of memory and my swap is set to 0. As of this moment I have 3 virtual machines running, my memory usage is 7.1 of 7.7 GB, my used swap is only at 576KB of 952MB and all systems are running smoothly!

From the Ubuntu SwapFAQ:

The swappiness parameter controls the tendency of the kernel to move processes out of physical memory and onto the swap disk. Because disks are much slower than RAM, this can lead to slower response times for system and applications if processes are too aggressively moved out of memory.

  1. swappiness can have a value of between 0 and 100
  2. swappiness=0 tells the kernel to avoid swapping processes out of physical memory for as long as possible
  3. swappiness=100 tells the kernel to aggressively swap processes out of physical memory and move them to swap cache

Below are basic instructions for checking swappiness, emptying your swap and changing the swappiness to 0:

To check the swappiness value:

cat /proc/sys/vm/swappiness

To temporarily set swap to 0 (as suggested by SpamapS):

This will empty your swap and transfer all the swap back into memory. First make sure you have enough memory available by viewing the resources tab of gnome-system-monitor, your free memory should be greater than your used swap. This process may take a while, use gnome-system-monitor to monitor and verify the progress.

sudo swapoff --all

To set the new value to 0:

sudo sysctl vm.swappiness=0 

To turn swap back on:

sudo swapon --all

To permanently set swappiness to 0:

  1. sudoedit /etc/sysctl.conf
  2. Add this line vm.swappiness = 0
  3. sudo shutdown -r now # restart system

* With kernel version 3.5+ setting swappiness to 0 does turn it off entirely and a setting of 1 is recommended if you want the lowest swappiness algorithm. source: https://www.percona.com/blog/2014/04/28/oom-relation-vm-swappiness0-new-kernel/

  • 2
    I just updated the answer to include a permanent way to set swappiness. Not sure how it got upvoted so much, I am guessing nobody tested it. Commented Jul 1, 2015 at 13:23
  • 1
    More good reading on swappiness in this answer => askubuntu.com/a/103916/11929 Commented Jul 1, 2015 at 13:24
  • 3
    I'm not sure if this was available when the author originally posted the answer but a swappiness value of "60" is in place for ubuntu server installs since that environment has a different set of specifications for performance. help.ubuntu.com/community/…
    – Frito
    Commented Jun 6, 2016 at 14:10
  • 3
    This setting is very effective in controlling the size of the swap. My system has 16G RAM and 16G swap. Sometimes I'm running to VMs and some of my applications get swapped out. When I close the VMs the RAM usage drops, but the swap usage remains the same and my system lags when changing applications. Changing the swapiness has improved performance for me.
    – kapad
    Commented Aug 9, 2018 at 5:46
  • 2
    This should be the accepted answer really. Thorough explanation of the problem, and it's solution, as well as links and a solution to retain Swap memory, but help keep it under control in the first place. Awesome stuff. Thanks. :)
    – Jack_Hu
    Commented Jul 24, 2019 at 22:28

I've found that emptying swap can help a lot on systems with slow disks and limited RAM. Of course, as already mentioned, the way to do this is to run sudo swapoff -a; sudo swapon -a. The problem here is that if there's insufficient RAM, doing so will cause all sorts of problems.

I've written a script that I call toggle_swap that has worked for me for the last several years. It checks for enough free RAM before actually disabling the swap. Here it is:


mem_data="$(echo "$free_data" | grep 'Mem:')"
free_mem="$(echo "$mem_data" | awk '{print $4}')"
buffers="$(echo "$mem_data" | awk '{print $6}')"
cache="$(echo "$mem_data" | awk '{print $7}')"
total_free=$((free_mem + buffers + cache))
used_swap="$(echo "$free_data" | grep 'Swap:' | awk '{print $3}')"

echo -e "Free memory:\t$total_free kB ($((total_free / 1024)) MB)\nUsed swap:\t$used_swap kB ($((used_swap / 1024)) MB)"
if [[ $used_swap -eq 0 ]]; then
    echo "Congratulations! No swap is in use."
elif [[ $used_swap -lt $total_free ]]; then
    echo "Freeing swap..."
    sudo swapoff -a
    sudo swapon -a
    echo "Not enough free memory. Exiting."
    exit 1
  • Awesome I was looking for something like this. Maybe to be a little safer you could present the number and percentages and then ask, just to be absolutely sure.
    – Atherion
    Commented Jan 27, 2017 at 0:09
  • 4
    I've update the code and have created a gist based gist.github.com/Jekis/6c8fe9dfb999fa76479058e2d769ee5c
    – Jekis
    Commented Aug 24, 2017 at 8:06
  • This is the conclusion I reached after reading all the tips, like one should somehow make sure there is enough RAM indeed before killing swap. Thank you sir, wonderful script. Should be included in Ubuntu by default (not kidding, it really is a musthave.)
    – Apache
    Commented Aug 28, 2017 at 18:55
  • Except that if you run any new thing while turning off swap, and before it's back on - it won't have enough memory.
    – barteks2x
    Commented Nov 2, 2017 at 16:38
  • That depends on how much free memory you have. If there's enough free memory to hold everything in swap AND the new process, then there's no issue. If not then you're right. Commented Nov 3, 2017 at 12:56

After mucking around with swappiness for a couple of days, I've come to the conclusion that the kernel should be left to its own devices. It knows what it's doing, and it's optimized to give you the best experience.

Unless you have a really good reason for wanting that disk back, I'd leave it be.

  • 9
    I had some stuff in swap, vmstat showed me that swapin and swapout was happening, and Chrome was laggy af, while my CPU was barely used. Good enough reason, no?
    – xeruf
    Commented May 6, 2018 at 15:27
  • 1
    There are definitely cases where certain swapping on desktop makes it laggy. (not while it is swapping, but also after, when there is enough RAM, for long time after.) So at best this answer is only subjective experience which happens in some cases.
    – Cray
    Commented Sep 26, 2019 at 20:02

New anser 2023!

Some tips and tricks

In addition to all existing answer I want to share some tricks I use.

Reading free's output

First, ensure that output of free is not localized, for this you have to prepend command by LANG=C free -k:

               total        used        free      shared  buff/cache   available
Mem:        32739720     9436264     8704992      883044    15959152    23303456
Swap:       23437308     5450752    17986556

Where, if you compute buff/cache + available the result will be bigger than total! This is wrong!!

Just consider if available mem is bigger than used swap, before purging swap!

msgs=("NOT " "")
{ # read `free` output, ignore 1st line and all values but free and swaped.
    read _
    read -r _{,,,,,} avail
    read -r _ _ swaped _
} < <(LANG=C free -k)
printf 'Avail: %d swaped: %d Can %sunswap!\n' \
           "$avail" "$swaped" "${msgs[ avail > swaped ]}"
 Avail: 23303456 swaped: 5450752 Can unswap!

Alternative using /proc/meminfo instead of free

Accessing directly /proc/meminfo instead of running a fork to free, you could obtain same values by:

msgs=("NOT " "")
while read field val _; do
    case $field in
        MemAvailable: ) avail=$val ;;
        SwapTotal: )    declare -i swaped=$val ;;
        SwapFree: )     swaped+=-$val; break ;;
done < /proc/meminfo
printf 'Avail: %d swaped: %d Can %sunswap!\n' \
           "$avail" "$swaped" "${msgs[ avail > swaped ]}"
 Avail: 23303456 swaped: 5450752 Can unswap!

Purging swap swapoff -a.

I've build a little script that

  • correctly parse free's output,
  • show human readable swaped and avail memory,
  • offer to run swapoff - swaponn loop if user don't interact
  • then compute elapsed time used to unswap.

There is my script, based on bash V>5.0:


msgs=("NOT " "")
while read field val _; do
    case $field in
        MemAvailable: ) avail=$val ;;
        SwapTotal: )    declare -i swaped=$val ;;
        SwapFree: )     swaped+=-$val; break ;;
done < /proc/meminfo

txtsize() { # Convert integer into readable string, store result in $2 varname
    local i=$(($1>=1<<50?5:$1>=1<<40?4:$1>=1<<30?3:$1>=1<<20?2:$1>1023?1:0))
    local a=(K M G T P)
    ((i>4?i+=-2:0)) && a=(${a[@]:2}) && set -- $(($1>>20)) $2
    local r=00$((1000*$1/(1024**i)))
    printf -v $2 %.2f%s ${r::-3}.${r: -3} ${a[i]}

txtsize $avail havail
txtsize $swaped hswaped
printf 'Avail: %s (%d) swaped: (%s) %d Can %sunswap!\n' \
    "$havail" $avail "$hswaped" $swaped "${msgs[ avail > swaped ]}"
if (( avail > swaped )); then
    if read -sn 1 -t 5 -p\
        'Proceed in 5 seconds. Hit any key to stop now. '; then
        echo $'\nUser abort.'
            exit 0
    swapoff -a
    elapsedTime=00000$(( ${EPOCHREALTIME/.} - elapsedTime ))
    swapon -a
    elapsedMin=$(( 10#$elapsedTime / 60000000 ))
    elapsedSec=00000$(( 10#$elapsedTime % 60000000 ))
    printf 'Swap: %s purged in %d minutes and %.3f secs (%.4f").\n' \
        "$hswaped" "$elapsedMin" ${elapsedSec::-6}.${elapsedSec: -6} \
        ${elapsedTime::-6}.${elapsedTime: -6}


His ouptut look like:

Avail: 23.86G (25023596) swaped: (1.14G) 1192460 Can unswap!
Proceed in 5 seconds. Hit any key to stop now. 
Swap: 1.14G purged in 1 minutes and 51.166 secs (111.1661").

This script require root privilege. But you could edit them to add sudo before swapoff -a and swapon -a.

From there, as this opereation could take some time, I've built a Full purgeSwap script, showing progression with a nice progress bar and compute end time estimation, you my download here: 👉 purgeSwap.sh.

This answer is linked to this other one: How to find out which processes are using swap space in Linux?

About swapiness

I'm not totally convinced on how this compute percent of used memeory: including swap or not... For my tests, I'v seen swaping a lot before reaching percents configured in this kernel variable.

Anyway, for my servers, I still use:

echo 10 > /proc/sys/vm/swappiness

for running system that was not already configured by:

echo >/etc/sysctl.d/90-swapiness.conf  'vm.swappiness = 10'

before last reboot.

Use of vmstat 1

I often use this, but as I like graphical presentation, I've build (in 2009) a perl CGI, that could work in standalone:


This script is self-downloadable, work in any web server, but could be used directly on poor systems. Graphics are drawn in svg and rendered by your browser.

Sample of use:

wget -O vmstat.pl http://perso.f-hauri.ch/~felix/marcm/vmstat.cgi/download/vmstat.cgi
LANG=C perl vmstat.pl 
CGI::Pretty is DEPRECATED and will be removed in a future release. Please see https://github.com/leejo/CGI.pm/issues/162 for more information at /usr/share/perl5/CGI/Pretty.pm line 20.
Server started at port 8881

Yes, it's an old script Don't run them as root!!.

...Then you could connect with a browser:


Here 1'800 dots with a delay of 1 seconds make half hour graphs.


Tell the vm to not be so swappy, by resucing the swappiness, by

sudo sysctl vm.swappiness=10

or even not be swappy as much as possible by

sudo sysctl vm.swappiness=0

Please read the documentation of swapfile here: https://help.ubuntu.com/community/SwapFaq


It doesn't affect performance if your swap space is occupied. The only performance penalty is is stuff is going in/out of swap. If nothing is being swapped in/swapped out, then you don't have to worry about anything.

  • 13
    Yeah but if something is being swapped it does affect performance, hence this question.
    – quant
    Commented Feb 3, 2015 at 22:18
  • 1
    That is some real nonsense, usually big fallback swaps are on HDDs or generally on a slower device than RAM - if space runs out - existing stuff is swapped - like e.g. internet browser - and then you're practically using it from the slower device...
    – jave.web
    Commented Aug 13, 2019 at 13:22
  • Memory is usually being swapped way before RAM space is running out. This is controlled by the vm.swappiness parameter. As soon as swap space is occupied there will be a performance impact when a memory page is accessed that has been swapped out to disk.
    – lanoxx
    Commented Mar 16, 2020 at 16:40

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