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I'm trying to start a docker container with systemd as the init process so I can run multiple services from that container, and I get the following weird error:

Systemd is listed as PID 1 when I run top, but none of the services i've enabled through systemctl are running, and trying to systemctl status them gives me system has not been booted with systemd as init process (PID 1)

Here's my dockerfile:

FROM ubuntu:20.04

ENV container docker
ENV LC_ALL C
ENV DEBIAN_FRONTEND noninteractive

RUN sed -i 's/# deb/deb/g' /etc/apt/sources.list

RUN apt-get update \
    && apt-get install -y systemd systemd-sysv \
    && apt-get clean \
    && rm -rf /var/lib/apt/lists/* /tmp/* /var/tmp/*

RUN cd /lib/systemd/system/sysinit.target.wants/ \
    && ls | grep -v systemd-tmpfiles-setup | xargs rm -f $1

RUN rm -f /lib/systemd/system/multi-user.target.wants/* \
    /etc/systemd/system/*.wants/* \
    /lib/systemd/system/local-fs.target.wants/* \
    /lib/systemd/system/sockets.target.wants/*udev* \
    /lib/systemd/system/sockets.target.wants/*initctl* \
    /lib/systemd/system/basic.target.wants/* \
    /lib/systemd/system/anaconda.target.wants/* \
    /lib/systemd/system/plymouth* \
    /lib/systemd/system/systemd-update-utmp*

...assorted aptget installs...

ENV LOCAL="yes"

...assorted utils scripts...

RUN useradd --create-home fractal \
    && usermod -aG sudo fractal \ 
    && echo 'fractal:password1234567.' | chpasswd

...assorted utils scripts...

ADD bootstrap.sh /home/fractal
ADD entry.sh /home/fractal
ADD fractal-input.rules home/fractal

RUN chmod +x /home/fractal/bootstrap.sh \
    && chown -v -R fractal:fractal /home/fractal
RUN chown root:root /run/user
RUN chmod +x /home/fractal/entry.sh


...adding assorted services...

VOLUME [ "/sys/fs/cgroup" ]

RUN systemctl set-default multi-user.target
ENV init /lib/systemd/systemd


....assorted services enabled....

CMD ["/lib/systemd/systemd"]

1 Answer 1

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You cannot use systemd within a Docker container without major effort. Most people use something like supervisord instead.

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