I created a Python command that uploads a zip file to an FTP server

I want to run it every 5 minutes using cron jobs.

So I opened crontab using crontab -e and I added the following line

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The cron job does not work but when I run smart-cv.py archive from the terminal it works and I can see that the zip file is uploaded to the FTP server.

I have already tried restarting the cron server with service cron restart but it does not work

  • 1
    Welcome to Ask Ubuntu! Please do not post screenshots of the terminal. Paste the text directly to your question and apply code formatting.
    – Melebius
    May 27, 2019 at 6:15
  • 1
    A general tip to debug cronjobs is to send the full output to a log file, like */5 * * * * smart-cv.py archive >> /tmp/user-crontab.log 2>&1, then open another console and run tail -f /tmp/user-crontab.log to see the output live while it runs. You can change the path of the log file to your home folder.
    – bistoco
    May 27, 2019 at 8:05

1 Answer 1


Give the complete path of the python file. Change your command to

 5 * * * * /path-of-the-file/smart-cv.py archive 

Hope it helps.

  • The Python command that I created belongs to a custom module that I deployed. It's located in /usr/local/lib/python3.6/dist-packages/smart_cv-1.0.0-py3.6.egg/EGG-INFO/scripts. When I run smart-cv.py archive the terminal automatically searchs in the path so how can i tell cron to do the same ? May 24, 2019 at 12:14
  • You can add a PATH=$PATH:xxx assignment at the top of your crontab (actually anywhere before the command) May 24, 2019 at 12:29
  • @AmineMessaoudi Please edit your question to reflect all the details you posted in the comment. It helps to keep our Q&A style tidy and could also bring more attention since an edited question gets bounced on the homepage.
    – Melebius
    May 27, 2019 at 6:16

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