What I want to achieve:
I'd like to filter a system log file by date, i.e. when I do:
$ cat /var/log/syslog | grep -i "error\|warn\|kernel"
it prints lines like these for the three last days let say:
(...)
Apr 3 06:17:38 computer_name kernel: [517239.805470] IPv6: ADDRCONF(NETDEV_CHANGE): wlp3s0: link becomes ready
(...)
Apr 4 19:34:21 computer_name kernel: [517242.523165] e1000e: enp0s25 NIC Link is Up 1000 Mbps Full Duplex, Flow Control: None
(...)
Apr 5 09:00:52 computer_name kernel: [517242.523217] IPv6: ADDRCONF(NETDEV_CHANGE): enp0s25: link becomes ready
How to grep (select, or filter):
- by date?
- by date+hour?
What I tried:
$ cat /var/log/syslog | grep -i "Apr 5" | grep -i "error\|warn\|kernel"
It works as expected on the syslog
file, but not on the kern.log
file for example, which only returns: Binary file (standard input) matches
. And when I tail
this particular file I can see the same starting date format than in the syslog
file.
Question:
How to achieve the same on other logs like the kern.log
file?
In addition, is it possible to filter:
- by date range?
- by date+hour range?
Hint: if possible, with "easy-to-remember commands".