I have two folders with similar subfolder structures, which I would like to compare. For example:
A
├── child-1
├── child-2
├── child-3
├── child-4
├── child-5
and
B
├── child-1-some-text
├── child-2-more-text
├── child-3-nothing
├── child-6-random-text
├── child-7-more-random-text
I would like to list all those subfolders from A
which are prefix for a subfolder in B
and list corresponding subfolders from B
as well. The expected output is
child-1 -- child-1-some-text
child-2 -- child-2-more-text
child-3 -- child-3-nothing
A secondary requirement: If multiple matches in B
, then it should give an error / warning.
My solution:
cd A
for f in `ls -d */`;
do
cd B;
new_dirs=(`ls -1d $f*`);
cd -;
if [ ${#new_dirs[@]} -eq 0 ]
then
## DO_Nothing
continue;
elif [ ${#new_dirs[@]} -gt 1 ]
then
echo "Multiple matches to $f";
continue;
else
echo "Unique Match found to $f -- ${new_dirs[0]}";
continue;
fi;
done
Problem:
For those values of $f
, which have no corresponding subfolders in B
, the array construction is giving me an error. e.g.:
ls: cannot access 'child-4*': No such file or directory
Question
- How to get rid of these errors?
- Is there better way to achieve the goal(s) then the one in my code?
Thanks in advance!
diff -rq DIR1 DIR2
to compare not just directory structure, but file contents.