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I have an array of file names like below, I want to find and learn the sizes in the folder. I wrote the bash script below but it is finding all the files in the folder recursively.

files=( a/ddd/dd ddd/b dfgf/fgdfg/c dfgdfg/dfgdfg/d dsf/e rret/ertert/erter/f)

for u in "${files[@]}"  
do  
    find . "[^\/]+$" $u".js" -exec du -sh {} \;
done
  • 4
    Can you please edit your question to clarify what you are trying to do? Is dfgf/fgdfg/c.js a file whose size you want to know, or is dfgf/fgdfg/c a directory that contains *.js files whose size you want to know? – steeldriver Jan 31 '19 at 13:24
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From man find

-maxdepth levels
          Descend  at  most  levels  (a  non-negative  integer)  levels  of directories below the starting-points.
          -maxdepth 0
           means only apply the tests and actions to the starting-points themselves.

Try

find . -maxdepth 0 -name "[^\/]+$" $u".js" -exec du -sh {} \;

I rarely use find with -exec (because I always forget about it) so I apologize if this is wrong

| improve this answer | |
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    Please finish your answer by including the entire find command. Even though the question is unclear, you can re-edit your answer if the question is edited. – karel Jan 31 '19 at 13:44
  • The -exec part look fine to me, but I'm having a hard time understanding what -name "[^\/]+$" $u".js" is intended to do here. AFAIK -name takes a single simple shell glob (not a regex) as argument, and matches against only the filename portion (so a -name pattern can't contain slashes) – steeldriver Jan 31 '19 at 15:30
  • it might be the I interpreted the man page wrong :/ The metacharacters (``*', ``?', and ``[]') match a ``.' at the start of the base name – j-money Jan 31 '19 at 15:33

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