0

I am writing a few bash scripts and need some assistance with being able to find an executable file within a directory and assigning it to a variable.

so I know if I run:

ls -dF `find . -maxdepth 1 \( -perm -1 -o \( -perm -10 -o -perm -100 \) \) -print`

it will return something like this:

./ravend
./raven-cli

What I would like to do is have it return:

ravend
raven-cli

and then have something like:

coind='ravend' coincli='raven-cli'

I am assuming I would have to do something like this code example, but i just don't know how to write it

output=$(ps -ef | awk '/siebsvc –s siebsrvr/ && !/awk/ { a++ } END { print a }'); echo $output
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I would say doing something generic to get multiple results, and then using parts of that result to specific things is not a good idea. I would suggest doing a more targetd search for each of the variables.

Disregarding this, I had fun coming up with the following solution:

#!/usr/bin/env bash

main() {
    local coind coincli
    read -a executables -r < <(find . -maxdepth 1 -type f \( -perm -1 -o \( -perm -10 -o -perm -100 \) \) -printf "%f ")

    (( "${#executables[@]}" > 2 )) && { echo "Found more than 2 executables: ${executables[*]}"; return 1; }

    local word
    word="$(comm -12 --nocheck-order <(grep -o . <<<"${executables[0]}") <(grep -o . <<<"${executables[1]}") | awk '{printf $0}')"

    for executable in "${executables[@]}"; do
        local variable="${executable/${word}/coin}"
        variable="${variable//[^a-z]/}"
        declare "${variable}=${executable}"
    done

    echo "coind: ${coind}"
    echo "coincli: ${coincli}"
}

main "$@"
exit $?

find . -maxdepth 1 -type f \( -perm -1 -o \( -perm -10 -o -perm -100 \) \) -printf "%f " - find files with executable permission in current directory, and only print file name (no path)

comm -12 --nocheck-order <(grep -o . <<<"${executables[0]}") <(grep -o . <<<"${executables[1]}") - find the word/characters that exist in both executable names

grep -o . <<<"${executables[0]}" - split string into 1 character per line (done for both executables)

| awk '{printf $0}') - each character is printed on a new line, this is used to collapse it into a word

variable="${executable/${word}/coin}" - replace (once) the common word with coin (will be used to set the variables later)

variable="${variable//[^a-z]/}" - remove all characters that isn't anything of a through z (in this case, remove - from the variable name

declare "${variable}=${executable}" - dynamically declare variable and set it's value.

  • This is awesome! Thank you. I ran a couple of tests and this is getting me where I want to be. Question though, there will not always be a -cli executable file though. When I ran this with both files in the directory it worked flawless. When I ran it with the -cli file removed it returned nothing for both variables. – jonathan adams Sep 21 '18 at 13:54

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