How can I obtain list of items and their inode numbers in the current working directory ?
asked Sep 10, 2018 at 0:06
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@VolkerSiegel A comment ? That's an interesting reason. Can you explain what exactly you mean ?– Sergiy KolodyazhnyySep 10, 2018 at 5:39
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@VolkerSiegel It's intended as "canonical" question for the site, which can be used to close other questions. If someone comes with the same question, we can use this one as duplicate. But to argue the case, many canonical questions themselves look simplistic and "lacking research", and for a good reason - they're intended as questions that address the basics. Take for instance [this one](How to remove all files from a directory? ). I'm sure at the time when the question was creted, stackoverflow already had one; problem is that you can't close question on site A with link on site B– Sergiy KolodyazhnyySep 10, 2018 at 6:48
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Makes sense. I retracted my close vote.– Volker SiegelSep 10, 2018 at 7:10
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Today this question reached 1000 views. I think this serves as a somewhat testimony that it is a useful question– Sergiy KolodyazhnyyOct 7, 2019 at 0:03
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I agree. And I'll remove my older comments, as they are just confusing now. Thanks for pointing it out!– Volker SiegelOct 7, 2019 at 0:08
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2 Answers
ls has -i flag:
$ ls -i
1054235 a.out 1094297 filename.txt
But if you are feeling adventurous , build ls -i yourself:
#include <dirent.h>
#include <stdio.h>
#include <sys/stat.h>
#include <unistd.h>
#include <limits.h>
void print_dirents(DIR * dir){
struct dirent *entry;
while ( (entry=readdir(dir)) != NULL ){
printf("%s,%d\n",entry->d_name,entry->d_ino);
}
}
int main(){
char current_dir[PATH_MAX];
DIR *cwd_p;
if ( getcwd(current_dir,sizeof(current_dir)) != NULL){
cwd_p = opendir(current_dir);
print_dirents(cwd_p);
closedir(cwd_p);
} else {
perror("NULL pointer returned from getcwd()");
}
return 0;
}
And it works as so:
$ gcc lsi.c && ./a.out
filename.txt,1094297
a.out,1054235
..,1068492
.,1122721
lsi.c,1094294
answered Sep 10, 2018 at 0:07
stat ./*
or
man stat; stat --format=*f* ./*
Sergiy Kolodyazhnyy
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answered Sep 10, 2018 at 5:19
