Need to extract a substring from a file path string including the delimiter

Question

While executing a shell script, an input string is similar to this:

test1/test2/Test.jar/Test2.jar/com/test/ui/GI.class

How can I extract: test1/test2/Test.jar [i.e. substring till first occurrence of '.jar' delimiter, inclusive], in shell script

How can I do this? I would not like to use cut and then append '.jar' at the end.

Thanks

Answer 1

Besides sed, you also have the option of using grep for this, with the PCRE regex ^.*?\.jar:

grep -oP '^.*?\.jar' <<<"test1/test2/Test.jar/Test2.jar/com/test/ui/GI.class"

This prints only the match (-o), uses PCRE (-P), and matches text that:

• starts at the beginning of the line (^), and
• contains any character (.), any number of times but matched lazily (*?),
• followed by a literal . character (\.) and jar (jar)

Using the lazy quantifier *? instead of the usual greedy quantifier * causes grep to match the fewest characters possible.

• Without it (and with the greedy quantifier instead), grep would match as many characters as possible so long as the match ended in .jar, which would fail to stop after the first .jar in cases where there is more than one.
• The -P flag is required because, of the regex dialects grep supports on Ubuntu, PCRE is the one that supports laziness. (This dialect is very similar to the regex dialect in Perl.)

Answer 2

You could use sed like below:

sed 's/\(\.jar\).*/\1/' <<<"test1/test2/Test.jar/Test2.jar/com/test/ui/GI.class" 

Or through awk command:

awk -F'\\.jar' '{print $1".jar"}' <<<"test1/test2/Test.jar/Test2.jar/com/test/ui/GI.class"

The output is:

test1/test2/Test.jar

Answer 3

Since you mention shell scripting I present a simple, purely shell based solution:

s='test1/test2/Test.jar/Test2.jar/com/test/ui/GI.class'
echo "${s%%.jar*}.jar"

The parameter expansion %% removes the longest suffix that matches the subsequent glob pattern .jar* (as opposed to % which matches the shortest suffix).

Answer 4

In python:

python3 -c "print('blub/blab/Test.jar/blieb'.split('.jar')[0]+'.jar')"

> blub/blab/Test.jar

or:

python3 -c "s='blub/blab/Test.jar/blieb';print(s[:s.find('.jar')+4])"

> blub/blab/Test.jar

Answer 5

Since this question is tagged bash, here's a bash script with C-style loop and ${variable:beginning:offset} parameter expansion to extract individual characters

#!/usr/bin/env bash

substring=""
for ((i=0;i<=${#1};i++))
do
    substring="$substring""${1:$i:1}"
    if [[ "$substring" == *.jar ]]
    then
        echo "$substring"
        substring=""
    fi
done

This works like so in action:

$ ./parse_string.sh test1/test2/Test.jar/Test2.jar/com/test/ui/GI.class                                                                              
test1/test2/Test.jar
/Test2.jar

If we wanted to extract only the first occurrence, add break on line after substring="" inside if statement