How to Extract Hostname from Ansible Playbook Run [closed]

Question

I need to accomplish following shell script. I trying to extract the HOSTNAME after it runs Successful via Ansible Playbook Run.

I have text file which contains Ansible-Playbook run command to be executed and writing the output into the log file: result.log

Here is what's the "result.log" file looks like

PLAY RECAP *********************************************************************
TESTLINUX01                : ok=6   changed=1    unreachable=0    failed=0

If the failed is "0", Unreachable is "0" and Changed is more then 0, then print the HOSTNAME only. In this case, TESTLINUX01

Thank you for your help.

Answer 1

You can use someting like this:

#!/bin/bash

file="result.log"

changed=`grep -Po "changed=\K\d+" $file`
unreachable=`grep -Po "unreachable=\K\d+" $file`
failed=`grep -Po "failed=\K\d+" $file`

if [ $changed -ge 1 -a $unreachable -eq 0 -a $failed -eq 0 ]
 then
  cut -s -f1 -d: $file | tr -s ' '
fi

---

First we extract all necessary values then we compare them with your desired ones, if they where match we print out the host name.

• grep -Po "changed=\K\d+ returns the number in front of "changed"
• IF statement:
  • $changed -ge 1 if changed is greater that equal "1"
  • -a and
  • $unreachable -eq 0 unreachable was equal to "0"
  • -a and
  • $failed -eq 0 failed was equal to "0", Then:
• cut -s -f1 -d: $file | tr -s ' ' prints the hostname

Answer 2

Thank you all for replying and providing the solution. Following code works out for me:

cat $file
$file >> $LOGFILE

SUCCESS=`grep "unreachable=0    failed=0" $LOGFILE | awk '{printf "%s ", $1;}'`
echo "Success: $SUCCESS"

FAILURE=`grep -E "unreachable=0    failed=[1-9]" $LOGFILE | awk '{printf "%s ", $1;}'`
echo "Failure: $FAILURE"

Unreachable=`grep -E "unreachable=1    failed=0" $LOGFILE | awk '{printf "%s ", $1;}'`
echo "Unreachable: $Unreachable"