PHP shell_exec() in ubuntu

Question

I am using ubuntu with libreOffice. I have installed unoconv for convert a *.odp file to *.pdf. When i run the command unoconv -f pdf myfile.odp from terminal then it works very fine. I want to do the same thing with using PHP shell_exec() method. So, I wrote the following code:

$output = shell_exec('unoconv -f pdf test.odp 2>&1');
echo $output;

But it shows the following error:

/usr/bin/python: /opt/lampp/lib/libz.so.1: no version information available (required by /usr/bin/python) 
Traceback (most recent call last): File "/usr/bin/unoconv", line 24, in import uno,
unohelper File "/usr/lib/python2.7/dist-packages/uno.py", line 34, in import pyuno SystemError: dynamic module not initialized properly

How can I solve this problem?

Thanks in advance.

Answer 1

Apach may be configured to disallow calling some command/libs...

But maybe environment variables (e.g. $PATH...) are not just the same for your user and Apach user (www-data) or something like that.

Here is an example what you can do to search the issue:

Try to call set or setenv to get the list of the variables.

Create a basic script callset.sh:

#!/bin/bash
set

(do not forget chmod +x callset.sh to give execution permission):

Then call this bash script from PHP:

$output = shell_exec ('/your/dir/callset.sh 2>&1');
echo $output

or

exec ("/your/dir/callset.sh", $output, $exitstatus);
print_r ($output);

Then check the difference with your own set call.

Finally provide the missing variables like that:

$output = shell_exec('PATH=aaa:bbb:ddd unoconv -f pdf test.odp 2>&1');