I've seen tons of topics about this but i couldn't find anything that answers to my question:
How can I install Ubuntu with UEFI enabled BUT making windows boot by default without showing GRUB and if i want to boot Ubuntu I press the F12 key (in my case) before booting to boot ubuntu?
Explaining: I have an Acer aspire E5-511 with windows 8.1 pre installed, then i updated to windows 10, now i'd like to install ubuntu but I don't want GRUB to show up when i want to boot windows i want windows to boot normally without it, but make it that Ubuntu boots directly from the boot selection menu pressing F12 and selecting it's partition.
As far as i know, I must create a "/" partition, a swap partition and an EFI partition in Fat32, but i don't know where to install the GRUB loader, in /dev/sda? or /dev/sda5 (efi partition)? or /dev/sda6 (ubuntu partition)? to make it show up ONLY when i select it from boot menu.
Boot Process by default: Power button > boot windows normally
Boot process to boot ubuntu: Power button > Press F12 > Boot selection menu > select Ubuntu/GRUB partition > boot Ubuntu ( without or with)
I don't know if you understood what i want to do :P
EDIT: I'm running UEFI. I can't disable it, for some reason if I disable UEFI and Fast boot Windows won't boot then, I get a black screen with "Couldn't find booteable HDD" instead, so i must install Ubuntu in UEFI mode in order to dual boot with windows.
Try Ubuntu
, rungparted
and post a screen shot of that.) Edit your answer to reflect this additional information and then drop me a note @Fabby.