Show 1 to N on the terminal

Question

I am looking for simple thing just, foo 8 will shows this:

1
2
3
4
5
6
7
8

PS: I am looking just for command line. I know how to create that by using for on the bash

Answer 1

To print a sequence of number the command 'seq' is your friend

seq 8

Answer 2

{1..8} will give you a simple argument range in Bash.

If you need that line by line, I'd suggest feeding that to something like printf:

$ printf '%d\n' {1..8}
1
2
3
4
5
6
7
8

Answer 3

You can also use echo command with brace expansion

echo -e "\n"{1..8}

1 
2 
3 
4 
5 
6 
7 
8

If you don't want the initial newline, you can use one of the below commands.

echo -e "\n"{1..8}|tail -n8

echo -e "\n"{1..8}|grep .

echo -e "\n"{1..8}|grep [0-9]

echo -e "\n"{1..8}|sed 1d

Answer 4

Alternatively you can get it with simplest way as follows:

$ echo {1..8} | tr ' ' '\n'
1
2
3
4
5
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7
8

OR:

$ for ((i=1 ; i<=8 ; i++)) do echo $i ; done;
1
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7
8

8 can be replaced by your 'N' positive integer!

Answer 5

You could use this simple for command,

$ for i in {1..8}; do echo $i; done
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8

Through awk,

$ awk 'BEGIN{for(i=1;i<=8;i++) {print i;}}'
1
2
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8