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Is there any way to know what version of gcc is used by the make command? I have 5 versions installed of gcc on my computer: by dpkg -l | grep gcc

ii  gcc                                                   4:4.8.2-1ubuntu6                                    i386         GNU C compiler
ii  gcc-4.6                                               4.6.4-6ubuntu2                                      i386         GNU C compiler
ii  gcc-4.6-base:i386                                     4.6.4-6ubuntu2                                      i386         GCC, the GNU Compiler Collection (base package)
ii  gcc-4.8                                               4.8.2-19ubuntu1                                     i386         GNU C compiler
ii  gcc-4.8-base:i386                                     4.8.2-19ubuntu1                                     i386         GCC, the GNU Compiler Collection (base package)
ii  gcc-4.9-base:i386                                     4.9-20140406-0ubuntu1                               i386         GCC, the GNU Compiler Collection (base package)
ii  libgcc-4.8-dev:i386                                   4.8.2-19ubuntu1                                     i386         GCC support library (development files)
ii  libgcc1:i386                                          1:4.9-20140406-0ubuntu1                             i386         GCC support library
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closed as off-topic by Mitch Jul 17 at 17:28

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3 Answers 3

up vote 5 down vote accepted

Open the terminal and type:

gcc --version
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how to make sure which [make] use this one –  lion Jul 17 at 4:04
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@lion karel is telling you, the default version (printed with the command above) is used by make –  Lucio Jul 17 at 4:11
    
+1 ok but how to make sure |: D; –  lion Jul 17 at 4:18
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You can also explicitly switch from the default version of gcc (aka "auto mode") to a different version of gcc temporarily (manual mode) by following the instructions in this answer. –  karel Jul 17 at 4:18
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You may also need to check the makefile, some explicitly state a version. –  Vality Jul 17 at 13:02
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Makefiles often use implicit rules to compile things, rather than defining the compiler specifically. In this case, the convention (and default) is to use $(CC), which defaults to cc. So if you type cc --version, you'll see what Makefiles use by default.

The Makefile may override the definition of CC though, or not use $(CC) at all. But is the convention (as it is within autoconf for configure scripts, too).

Also see: http://stackoverflow.com/questions/2969222/make-gnu-make-use-a-different-compiler

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make only does whatever the Makefile tells it to do. Most Makefiles will use the default gcc command, so karel's answer applies in most cases, but you should be aware that there's nothing that forces make to use the default GCC. (And for that matter, make can be used for a lot of things besides compiling C, so it might not even use GCC at all.)

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