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I am actually playing with arguments and its happened. I just thought like to see what will happen if I type $$1 and I did it and got something below.

raja@raja-BONEFISH:~$ $$1
19301: command not found

What's that 19301 mean, is it telling something?

Bottom-Line: what does meaning for $$1 in bash.

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ouch!! that much easy thing. I am still have many things to learn. All answers are super. +1 to all. – Raja May 20 '14 at 17:55
up vote 25 down vote accepted

$$ is the PID (process id) of the current process.

$$1 is the above PID followed by the literal string 1.

So it is telling you that your bash is the process with PID 1930.

But... free trick:

show() { eval echo \$$1; }
show PATH

(quite convoluted, ain't it?)

More info in TLDP.

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See also - – bodhi.zazen May 20 '14 at 17:54
For a moment I read the TLDP as "Too Long Didn't Pee". – Luis Alvarado May 27 '14 at 0:07
  • $$ - pid of the current shell (not subshell) - see What are the special dollar sign shell variables?

  • $$1 - pid of the current shell (not subshell) followed by 1.

  • $$2 - pid of the current shell (not subshell) followed by 2.

  • $$a - pid of the current shell (not subshell) followed by a character.

  • And so on...

See the output of echo $$1.

And you get the error command not found because you are trying to execute a string composed of digits which obviously is not a command.

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You have concatenated $$ and 1 together to get the PID of the current shell and 1, i.e. $$ stands for the PID of the currently running shell and 1 is just a character, you could do $$a, $$@ to get the PID concatenated with the following character.

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$$ it will state 1930 which is pid of current shell .

When you type $$1 that means pid followed by one so you the output would be 19301 .

Try $$2 the output will be 19302

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