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I have a few hundreds of files that has this pattern

  2 H18 65.2220 Du 1 RES1 0.0000
 1  3  5  ar

among them, some of the files are missing the line after the @<TRIPOS>BOND and they look like

  2 H18 65.2220 Du 1 RES1 0.0000

I'm trying to find all the files in my working directory that are missing the numeric line after the @<TRIPOS>BOND and move them to another directory. I know this is a simple task, but I am quite new to Linux.

Note: the files vary in length and line numbers, this is why I am "grepping" the line after the @<TRIPOS>BOND string.

Here's one of my codes, which I was planning to write in a for loop. It doesn't do the job, but I am showing it to show one of my trials.

cat file | grep -A1 '@<TRIPOS>BOND' | awk 'FNR == 2 {print}'

Thank you

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4 Answers 4

up vote 6 down vote accepted

If your version of grep supports PCRE mode (-P) you could try a multiline match that finds instances of @<TRIPOS>BOND that are followed (after only a newline) by @<TRIPOS>SUBSTRUCTURE e.g.


The \Q and \E may be unnecessary in this case but are intended to force literal matching (in case @, >, < have special meaning in the Perl regex syntax). The -l tells grep to list the matching files instead of printing the match. You can then use the list of files as an input to the mv command e.g.

grep -lzP '\Q@<TRIPOS>BOND\E\n\Q@<TRIPOS>SUBSTRUCTURE\E' * | xargs mv -t /path/to/newdir/

Additional info

You could express the second part of the match as a lookahead but I don't think it has any advantage in this case


Equivalent expressions in pcregrep (which is not part of the standard Ubuntu system, but obtainable from the repository) would be something like



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How about

for file in *.txt; do 
    grep -A1 "@<TRIPOS>BOND" "$file" | grep -q SUBSTR && mv "$file" bad_files/


This will loop through all .txt files in the current directory (change to the blob to whatever matches your files) and save each as $file. It will then search $file for @<TRIPOS>BOND and print that and the next line. This is passed through the next grep which silently (-q) looks for SUBSTR, if it finds it, it means that the line after BOND is SUBSTRUCTURE and not the numeric line you want so it will move the current file to the folder bad_files.

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+1 Seems much simpler than mine ^^ –  chaos May 7 '14 at 11:28

It's not that simple:

find -type f -exec \
 awk '/@<TRIPOS>BOND/{getline; \
  if ($0 !~ /1  3  5  ar/){\
  printf "mv %s /path/to/move/%s\n", FILENAME, FILENAME}}' {} \; \
| bash


  • find -type f: Find all files in the current working directory
  • awk '/@<TRIPOS>BOND/{getline; \: find the line inside the file and move to the next line
  • if ($0 !~ /1 3 5 ar/){\: If the next line is NOT (!~) your desired "numeric line"
  • printf "mv %s /path/to/move/%s\n", FILENAME, FILENAME}}' {} \; \: build an mv command and pipe it to...
  • | bash: ...bash and execute it.

So the command will mv all file that are not contianing the numeric line to a directory called /path/to/move/.

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I think the OP's numeric line can change. I doubt it will be the same for all bonds. –  terdon May 7 '14 at 10:55
Then he can replace if ($0 !~ /1 3 5 ar/) with if ($0 ~ /@<TRIPOS>SUBSTRUCTURE/) –  chaos May 7 '14 at 11:24
Indeed. Or, simpler if ($1 !~ /^[0-9]$/), that way you don't need to worry about multiple spaces or tabs. –  terdon May 7 '14 at 11:27
nawk '/^@<TRIPOS>BOND/{getline;if( $0 ~ /^@/){print "mv", FILENAME, "../NewLoc/"}}' * | bash
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