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I'm running a Web Server in a Virtual Box for testing some projects. And I noticed that some of the html files have this unwanted lines. I want these lines of code from multiple html/htm files removed so I did it like this:

find /Desktop/TEST_REMOVAL3/ -name '*.html' -or -name '*.htm' -or -name '*.php' | sed -i "/<SCRIPT Language=VBScript>/,/ //--></SCRIPT><!-- /d"

So far, the 1st part where if looks/finds all html files works. The part where I need to remove the lines starting from <SCRIPT Language=VBS> to </SCRIPT> using sed fails :D

I'll try to figure it out again while waiting for your suggestions and scolding on where I went wrong :D

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Close voters: This question is not off-topic! Questions about shell scripting and bash are perfectly fine here as long as the OP is running Ubuntu. – Seth Apr 23 '14 at 0:22
up vote 4 down vote accepted

If you want to use the file list from find as arguments for the sed command (instead as imput, which is what your line is doing), you have to use either the xargs command:

find dir -name '*.html' | xargs -d \\n sed -i "COMMANDS"

In which case xargs takes the file list, using newline (\n) as separator between file names and starts sed with them as arguments.

Or you use the -exec option of find:

find dir -name '*.html' -exec sed -i "COMMANDS" {} +

In which case find will run the command between -exec and + while replacing {} with (a list of) file names. There is also

find dir -name '*.html' -exec sed -i "COMMANDS" {} \;

which does essentially the same, but starts a new sed for every single file name.

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Also, simplify your sed statements and use single quotes , sed -i '/VBScript/,/SCRIPT>/d' , you do not need to match the entire line – bodhi.zazen Apr 22 '14 at 19:14

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