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I have two directories that should contain the same files and have the same directory structure.

I think that something is missing in one of these directories.

Using the bash shell, is there a way to compare my directories and see if one of them is missing files that are present in the other?

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What is the output of bash --version? – i08in Feb 16 '14 at 17:10

You can use the diff command just as you would use it for files:

diff <directory1> <directory2>

If you want to see subfolders and -files too, you can use the -r option:

diff -r <directory1> <directory2>
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Didn't know diff works for directories as well(man diff confirmed that), but this doesn't recursively check for changes in subdirectories inside subdirectories. – i08in Feb 16 '14 at 17:04
@Jobin That's strange... For me, it does work. – Alex R. Feb 16 '14 at 17:07
I have something like this: a/b/c/d/a, x/b/c/d/b. See what diff a x gives you. – i08in Feb 16 '14 at 17:09
You have to use the -r option. That (diff -r a x) gives me: Only in a/b/c/d: a. only in x/b/c/d: b. – Alex R. Feb 16 '14 at 17:11
Cool! It works! +1. Diff just got more powerful(for me)! :) – i08in Feb 16 '14 at 17:12

Here is an alternative, to compare just filenames, and not their contents:

diff <(cd folder1 && find . | sort) <(cd folder2 && find . | sort)

This is an easy way to list missing files, but of course it won't detect files with the same name but different contents!

(Personally I use my own diffdirs script, but that is part of a larger library.)

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You'd better use process substitution, not temp files... – mniip Feb 16 '14 at 18:03
Good suggestion, thanks. – joeytwiddle Feb 17 '14 at 5:16
Note that this does not support file names with certain special characters, in that case you might want to use zero-delimiters which AFAIK diff is not supporting as of now. But there is comm which is supporting it since… so once it comes to a coreutils near you, you can do comm -z <(cd folder1 && find -print0 | sort) <(cd folder2 && find -print0 | sort -z) (whose output you might have to further convert in the format you need using the --output-delimiterparameter and additional tools). – phk Mar 5 at 21:52

Through you are not using bash, you can do it using diff with --brief and --recursive:

$ diff -rq dir1 dir2 
Only in dir2: file2
Only in dir1: file1

The man diff includes both options:

-q, --brief
report only when files differ

-r, --recursive
recursively compare any subdirectories found

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If you want to make each file expandable and collapsible, you can pipe the output of diff -r into Vim.

First let's give Vim a folding rule:

mkdir -p ~/.vim/ftplugin
echo "set foldexpr=getline(v:lnum)=~'^diff.*'?'>1':1 foldmethod=expr fdc=2" >> ~/.vim/ftplugin/diff.vim

Now just:

diff -r dir1 dir2 | vim -

You can hit zo and zc to open and close folds. To get out of Vim, hit :q<Enter>

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