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I want to insert in my script a value (string) that I would read from a text file.

For example, instead of:

echo "Enter your name"
read name

I want to read a string from another text file so the interpreter should read the string from the file and not the user input.

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What does your text file look like? Is the entire file 1 variable or are they KEY=VALUE pairs? The solutions are quite different (if it's the latter, Takkat's answer applies, the former Radu's) – minerz029 Oct 28 '13 at 11:37
Possible cross site duplicate of:… – Ciro Santilli 巴拿馬文件 六四事件 法轮功 Mar 24 '14 at 9:03
@CiroSantilli it is not crossposted if it was posted by a different user, there is no such thing as a "cross-site duplicate". The only thing that should be avoided is the same question asked by the same user on different sites. – terdon Mar 24 '14 at 17:52

To read variables from a file we can use the source command or . operator

Lets assume the file contains the following line

MYVARIABLE="Any string"

we can then import this variable using


source <filename>
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Whoever downvoted this answer has a problem. The answer is good and elegant, vote up! – Radu Rădeanu Oct 28 '13 at 9:58
One reason why you might not want to do it this way is because whatever is in <filename> will be run in your shell, such as rm -rf /, which could be very dangerous. – Mark Ribau Jan 10 '15 at 2:57
Deserve to be marked as answer – Ali Oct 27 '15 at 4:44
Late to the party, but, no, it doesn't deserve to be marked up OR as the answer. This sources another bash source file which is NOT what the OP asked for. He asked how to read the contents of a FILE into a variable. NOT how to execute another script which sets a variable. The correct answer is the one below. name=$(cat "$file") . – Richard Riley Nov 24 '15 at 12:54

Considering that you want all the content of your text file to be kept in your variable, you can use:


file="/path/to/filename" #the file where you keep your string name

name=$(cat "$file")        #the output of 'cat $file' is assigned to the $name variable

echo $name               #test

Or, in pure bash:


file="/path/to/filename"     #the file where you keep your string name

read -d $'\x04' name < "$file" #the content of $file is redirected to stdin from where it is read out into the $name variable

echo $name                   #test
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I dont want to display the variable, I want that this variable should be read by the script for further processing. I have tried awk which reads line by line. – user208413 Oct 28 '13 at 8:48
Ok, delete echo $name . I use it just for test. Next you can use $name variable for further processing anywhere you want in your script. – Radu Rădeanu Oct 28 '13 at 8:51
I cant use it anywhere it my script because dhe script doesn't know the value of the variable. In our case the variable name. – user208413 Oct 28 '13 at 9:28
@user208413 The value of $name variable is the string from your file assigned using cat $file command. What is not clear or so difficult to understand? – Radu Rădeanu Oct 28 '13 at 9:36
It's redundant to use a seperate $file variable if you're only using it once to load the $name variable, just use cat /path/to/file – minerz029 Oct 28 '13 at 10:05

From within your script you can do this:

read name < file_containing _the_answer

You can even do this multiple times e.g. in a loop

while read LINE; do echo "$LINE"; done < file_containing_multiple_lines
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or for a file with multiple items on each line . . . grep -v ^# file |while read a b c; do echo a=$a b=$b c=$c; done – gaoithe Sep 1 '15 at 14:29

One alternative way to do this would be to just redirect standard input to your file, where you have all the user input in the order it's expected by the program. For example, with the program (called

echo "Enter your name:"
read name
echo "...and now your age:"
read age

# example of how to use the values now stored in variables $name and $age
echo "Hello $name. You're $age years old, right?"

and the input file (called


you could run this from the terminal in one of the following two ways:

$ cat | ./
$ ./ <

and it would be equivalent to just running the script and entering the data manually - it would print the line "Hello Tomas. You're 26 years old, right?".

As Radu Rădeanu has already suggested, you could use cat inside your script to read the contents of a file into a avariable - in that case, you need each file to contain only one line, with only the value you want for that specific variable. In the above example, you'd split the input file into one with the name (say, and one with the age (say,, and change the read name and read age lines to name=$(cat and age=$(cat respectively.

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I have the following script: vh = awk "NR==3{print;exit}" /var/www/test/test.txt with this I read line 3 from text file named test.txt. Once i get a string I want to use this string as an input for creating a directory – user208413 Oct 28 '13 at 10:18
Change that to vh=$(awk "NR==3 {print;exit}" /var/www/test.txt). You will then have the string saved in variable $vh, so you can use it like so: mkdir "/var/www/$vh" - this will create a folder with the specified name inside /var/www. – Tomas Lycken Oct 28 '13 at 11:09
I have done this way but it still cant create the folder :( – user208413 Oct 28 '13 at 11:34
@user208413: What error message(s) do you get? "It doesn't work" is, unfortunately, not a very helpful problem description... – Tomas Lycken Oct 29 '13 at 11:02

If you want to use multiple strings, you could go with:

for p in `cat "$path"`;
do echo "$p" ....... (here you would pipe it where you need it) 


If you want the user to indicate the file

read -e "Specify path to variable(s): " path;
for p in 'cat "$path"';
do echo "$p" ............................
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Short answer:

name=`cat "$file"`
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I found working solution here:

if [ -f $SETTINGS_FILE ];then
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