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I would like to know is it possible to copy line number 7,8,9 and 17,18 of one text file to another one?

Thanks much in advance!!!

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up vote 2 down vote accepted

You can use sed (stream editor) to selectively print lines by number e.g.

sed -n '7,9p;17,18p' oldfile > newfile
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Thank you much for your help!!!! – yyyzzz Oct 6 '13 at 17:11

you should not rely on the order of the lines on a file, because it might change (if it is a system file, a temp file ecc. and it's updated).
You can use grep or one of its variants, for example rgrep:

rgrep WordOrRegularExpressionToMatch "Name_of_the_file"

Then, after you see that the lines printer are right, you can use:

rgrep WordOrRegularExpressionToMatch "Name_of_the_file" >> "Name_of_the_second_file"

It will append the lines printed by rgrep to the second file; to overwrite use ">" and not ">>".
If you really want to extract a precise set of lines you can use "sed":

sed -n -e 7,9p -e 17,18p "Name_of_the_file"

(these are 2 separate intervals)


sed -n -e 7,9p -e 17,18p "Name_of_the_file" > "Another_file_to_overwrite"

(>> to append> Copy & paste the line: it will do the job. :-)
"man sed" will give you more help.
Have a nice day!

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If you know how many lines are there in your source file (wc -l) you can do this .. assume 12000 lines and you want lines 2000 - 7000 in your new file (total of 5000 lines).

cat myfile | tail -10000 | head -5000 > newfile

Read the last 10k lines, then read the 1st 5k lines from that.

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Thank you much for your help!!! It is very interesting approach, thank you. – yyyzzz Oct 6 '13 at 17:13
You could at least post the link to the original answer :… .. or do the decent thing and answer it without the use of copy/paste .. – FreudianSlip Oct 6 '13 at 17:42

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