How do I capture the output of a command and put it in a label?

Question

This is an extract from the code of a Quickly application I'm working on:

# Code for other initialization actions should be added here.

self.apachestart = self.builder.get_object("apachestart")
self.label1 = self.builder.get_object("label1")

def on_apachestart_clicked(self, widget):
    subprocess.call(['sudo', 'service', 'apache2', 'start'])   

Now when I press the button to start Apache (named apachestart), it prints to standard out in the terminal that the server was started:

* Starting web server apache2  [ OK ] 

How do I get that text output from the terminal to be shown in a label?

Answer 1

This is not really a Quickly question, but a pure Python one.

Have a look at the Subprocess documentation, especially the check_output method.

You could do something like this (untested):

def on_apachestart_clicked(self, widget):
    result = subprocess.check_output(['sudo', 'service', 'apache2', 'start'])
    if result.split('[ ')[1].startswith('OK'):
        text = "Success!"
    else:
        text = "Failed!"
    self.label1.set_text(text)

Maybe also catch the CalledProcessError in the call.