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Using a Python script, I want to be able to open an image and close it on ubuntu.

Looking at the answer here:

http://stackoverflow.com/questions/6725099/how-can-i-close-an-image-shown-to-the-user-with-the-python-imaging-library

Specifically this line: viewer = subprocess.Popen(['some_viewer', infile])

What should I put as the 'some_viewer'?

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Once you have imagemagick installed you will get a command line option called display along with it.So you can easily use viewer = subprocess.Popen(['display',infile]) . –  Vinit Jul 27 '12 at 8:14
    
Any reason you need a subprocess for this? Look e.g. at this: stackoverflow.com/questions/10270080/… or: stackoverflow.com/questions/11549480/… –  Takkat Jul 27 '12 at 14:34

1 Answer 1

You can use "gvfs-open" to launch the default application for the filetype.

e.g. gvfs-open test.png would open test.png in GPicView on my system, and GIMP on a system where the user has set the default application for opening png files to GIMP.

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