How to avoid duplicate entries in .bash_history

Question

The same command is listed in my history again and again. How can I avoid this? I know it's possible via HISTCONTROL but I haven't found the right way.

Answer 1

From the bash man page:

HISTCONTROL

A colon-separated list of values controlling how commands are saved on the history list. If the list of values includes ignorespace, lines which begin with a space character are not saved in the history list. A value of ignoredups causes lines matching the previous history entry to not be saved. A value of ignoreboth is shorthand for ignorespace and ignoredups. A value of erasedups causes all previous lines matching the current line to be removed from the history list before that line is saved. Any value not in the above list is ignored. If HISTCONTROL is unset, or does not include a valid value, all lines read by the shell parser are saved on the history list, subject to the value of HISTIGNORE. The second and subsequent lines of a multi-line compound command are not tested, and are added to the history regardless of the value of HISTCONTROL.

So put the following line in your ~/.bashrc:

export HISTCONTROL=ignoreboth:erasedups

Answer 2

Stick this in your ~/.bashrc:

export HISTCONTROL=ignoredups

You could instead use ignoreboth. This it shorthand for both ignorespaces (commands starting with spaces) and ignoredups (duplicates).

I prefer ignoredups on its own as I find the default behaviour of ignoring commands with spaces at the front quite annoying when I copy a command off a website and it doesn't get saved because I accidentally copied in a space too.... But to each their own.

Answer 3

Add the following to your ~/.bashrc:

export HISTCONTROL=ignoredups

To do this, you can use this command:

nano ~/.bashrc

Answer 4

export HISTCONTROL=erasedups

Answer 5

re: "How to copy all those commands from history without numbering?"

alias hist='history | sed '\''s/^[ 0-9]* //'\'''